What is the effect of increasing pressure on the dissociation of PCl5 according to the equation?
PCl5 (g) PCl3 (g) + Cl2 (g)
Dissociation decreases
Dissociation increases
Dissociation does not change
None of the above
A.
Dissociation decreases
According to Le-Chatelier principle the reactions in which member of moles are increasing in forward reaction are favoured at low pressure or high volume.
PCl5 (g) PCl3 (g) + Cl2 (g)
Since, number of moles are increasing in the forward reaction in above reaction.
Reaction is favoured at low pressure. At high pressure, rate of dissociation of PCl5 decreases.
The ground state term symbol for an electronic state is governed by :
Heisenberg's principle
Hund's rule
Aufbau principle
Pauli exclusion principle
Pauling's electronegativity values for elements are useful in predicting :
polarity of bonds in molecules
position of elements in electromotive series
co-ordination number
dipole moment of various molecules
The trigonal bipyramidal geometry results from the hybridisation :
dsp3 or sp3d
dsp2 or sp2d
d2sp3 or sp3d2
d3p2 or d2p3
Two moles of PCl5 were heated in a closed vessel of 2 L. At equilibrium, 40% of PCl5 is dissociated into PCl3 and Cl3. The value of equilibrium constant is :
0.53
0.267
2.63
5.3
What is the effect of having the pressure by doubling the volume on the following system at 500°C?
H2 (g) + I2 (g) 2HI (g)
Shift to reactant side
Shift to product formation
Liquefaction of HI
No effect