Subject

Chemistry

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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21.

The crystal field stabilization energy (CFSE) of [Fe(H2O)6]Cl2 and K2[NiCl4], respectively are:

  • -2.4 Δ0 and -1.2Δt

  • -0.4 Δ0 and -1.2Δt

  • -0.6 Δ0 and -0.8Δt

  • -0.4 Δ0 and -0.8Δt


D.

-0.4 Δ0 and -0.8Δt

[Fe(H2O)6]Cl2: d6t2g4eg2: [(-0.4) 4 + 2(0.6)]Δ0

K2[NiCl4]  d8eg4t2g4:[(0.6)4+(0.4)4]Δt= -0.8Δt


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22.

1 g of a non-volatile non – electrolyte solute is dissolved in 100 g of two different solvents A and B whose ebulliscopic constants are in the ratio of 1:5. The ratio of the elevation in their boiling points, TbATbB is:

  • 1:0.2

  • 10: 1

  • 5: 1

  • 1: 5


23.

The correct order of the first ionization enthalpies is :

  • Ti < Mn < Ni < Zn

  • Mn < Ti < Zn < Ni

  • Ti < Mn < Zn < Ni

  • Zn < Ni < Mn < Ti


24.

The number of pentagons in C60 and trigons (triangles ) in white phosphours, respectively ,are :

  • 20 and 4

  • 20 and 3

  • 12 and 4

  • 12 and 3


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25.

For the reaction of H2 with I2, the rate constant is 2.5 × 10-4 dm3 mol-1s-1 at 327°C and 1.0 dm3 mol-1s-1 at 527°C. The activation energy for the reaction, in kJ mol-1 is: (R= 8.314 Jk-1mol-1)

  • 166

  • 150

  • 59

  • 72


26.

The correct statement is :

  • Zincite is a carbonate ore.

  • Zone refining process is used for the refining of titanium

  • Aniline is a for the stabilizer

  • Sodium cyanide cannot be used in the metallurgy of silver


27.

The highest possible oxidation states of uranium plutonium , respectively are

  • 6 and 7

  • 7 and 6

  • 4 and 6

  • 6 and 4


28.

The major product ‘Y’ in the following reaction is :


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29.

Compound A(C9H10O) shows positive iodoform rest. Oxidation of A with KMnO4/ KOH gives B(C8H6O4). Anhydride of B is used for the preparation of phenolpthalein. Compound A is:


30.

Which of the following is NOT a correct method if the preparation of benzylamine from cyanobenzene ?

  • H2/ Ni

  • (i) LiAlH4

    (ii) H3O+

  • (i) SnCl2 + HCl(gas)

    (ii) NaBH4

  • (i) HCl/H2

    (ii) NaBH4


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