Subject

Mathematics

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

Advertisement

81.

The differential equation representing a family of circles touchmg the Y-axis at the origin is

  • x2 +y2 - 2xydydx = 0

  • x2 +y2 + 2xydydx = 0

  • x2 -y2 - 2xydydx = 0

  • x2 -y2 + 2xydydx = 0


D.

x2 -y2 + 2xydydx = 0

Since, the circle touches the Y-axis, therefore the centre lies on the X-axis. Let the centre be (h,0).

 Radius of circle = h The equation of circle is given byx - h2 + y - 02 = h2    x2 +y2 - 2hx = 0      ...iOn differentiating both sides w.r.t x, we get2x +2ydydx - 2h = 0 h = x + ydydxPutting the value of h in Eq. (i), we get x2 +y2 - 2xx + ydydx = 0  - x2 +y2 - 2xydydx = 0     x2 - y2 + 2xydydx = 0This is the required differential equation.


Advertisement
82.

The area of the region bounded by the curve 9x2 + 4y2 - 36 = 0 is

  • 9π

  • 5π

  • 36π

  • 6π


83.

The general solution of the differential equation (2x - y + 1)dx + (2y - x + 1) dy = 0 is

  • x+ y2 + xy - x + y = c

  • x+ y2 - xy + x + y = c

  • x2 - y2 + xy - x + y = c

  • x2 - y2 - xy + x + y = c


Advertisement