Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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81.

Suppose f is such that f(- x) = - f(x), for every x and 01fxdx = 5, then - 10ftdt is equal to

  • 10

  • 5

  • 0

  • - 5


D.

- 5

Let  I = - 10ftdt = - 0- 1ftdtPut t = - x and dt = - dx  I = 01f- xdx = - 01fxdx                 f- x = - fx                01fxdx = 5       = - 5


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82.

The general solution of the differential equation ydx + (1 + x2) tan- 1(x)dy = 0, is

  • ytan-1x = c

  • xtan-1y = c

  • y + tan-1x = c

  • x + tan-1y = c


83.

Solution of differential equation dydx = 2xy is

  • y = cex2

  • y2 = 2x2 + c

  • y = ce- x2

  • y = x2 + c


84.

The second order differential equation is

  • y' + x = y2

  • y'y'' + y = sin(x)

  • y''' + y'' + y = 0

  • y' = y


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85.

The solution of the differential equation dydx - yx = 1 is

  • x2loge(x) + y = c

  • xloge(x) + cx = y

  • x2loge(x) - y = c

  • xloge(x) + y = cx


86.

An integrating factor of the differential equation 1 - x2dydx - xy = 1, is

  • - x

  • x1 - x2

  • 1 - x2

  • 12log1 - x2


87.

Withthehelp of Trapezoidal rule fornumerical integration and the following table

x 0 0.25 0.50 0.75 1
f(x) 0 0.625 0.2500 0.5625 1

the value of 01fxdx is

  • 0.35342

  • 0.34375

  • 0.34457

  • 0.33334


88.

The maximum value of z = 4x + 2y subject to the constraints 2x + 3y 18, x + y  10, x, y  0

  • 36

  • 40

  • 20

  • None of these


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89.

The maximum value of μ = 3x + 4y, subject to the conditions x + y 40, x + 2y 60, x, y 0, is

  • 130

  • 140

  • 40

  • 120


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