Subject

Mathematics

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

Advertisement

31.

y = easin-1x  1 - x2yn + 2 - 2n + 1xyn + 1 is equal to

  • - n2 + a2yn

  • n2 - a2yn

  • n2 + a2yn

  • - n2 - a2yn


C.

n2 + a2yn

Given, y = easin-1xOn differentiating w.r.t. x, we gety1 = easin-1x a . 11 - x2  y11 - x2 = ay 1 - x2y12 = a2y2Again, differentiating w.r.t. x, we get        1 - x22y1y2 - 2xy12 = a22yy1  1 - x2y2 - xy1 - a2y = 0

Using Leibnitz's rule,1 - x2yn + 2 + C1nyn +1- 2x + C2nyn- 2                         - xyn +1 - C1nyn - a2yn = 0 1 - x2yn + 2 + xyn + 1- 2n + 1                         + yn- nn - 1 - n - a2 = 0        1 - x2yn + 2 - 2n + 1xyn + 1 = n2 + a2yn


Advertisement
32.

The function f(x) = x3 + ax + bx + c, a2 3b has

  • one maximum value

  • one minimum value

  • no extreme value

  • one maximum and one minimum value


33.

In a ABCa + b + cb + c - ac + a - ba + b - c4b2c2 equals

  • cos2A

  • cos2B

  • sin2A

  • sin2B


34.

The angle between the lines whose direction cosines satisfy the equations l + m + n = 0, l2 + m2 - n2 = 0 is

  • π6

  • π4

  • π3

  • π2


Advertisement
35.

If m1, m2, m3 and m4 are respectively the magnitudes of the vectors

a1 = 2i^ - j^ + k^, a2 = 3i^ - 4j^ - 4k^,a3 = i^ + j^ - k^ and a4 = - i^ + 3j^ + k^,

then the correct order of m1, m2, m3 and m4 is

  • m3 < m1 < m4 < m2

  • m3 < m1 < m2 < m4

  • m3 < m4 < m1 < m2

  • m3 < m4 < m2 < m1


36.

ddxatan-1x + blogx - 1x + 1 = 1x4 - 1  a - 2b is equal to

  • 1

  • - 1

  • 0

  • 2


37.

2 - sin2x1 - cos2xexdx is equal to

  • - excotx + c

  • excotx + c

  • 2excotx + c

  • - 2excotx + c


38.

If In = sinnxdx, then nIn - n - 1In - 2 equals

  • sinn - 1xxcosx

  • cosn - 1xsinx

  • - sinn - 1xcosx

  • - cosn - 1xsinx


Advertisement
39.

The line x = π4 divides the area of the region bounded by y = sin(x), y = cos(x) and x - axis 0  x  π2 into two regions of areas A1 and A2. Then, A1 : A2 equals

  • 4 : 1

  • 3 : 1

  • 2 : 1

  • 1 : 1


40.

The solution of the differential equation dydx = sinx + ytanx +y - 1 is

  • cscx +y + tanx + y = x +c

  • x + cscx + y = c

  • x + tanx + y = c

  • x + secx + y = c


Advertisement