Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsShort Answer Type

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81.

Prove that the equation cos(2x) + asin(x) = 2a - 7 possesses a solution if 2  a  6.


cos(2x) + asin(x) = 2a - 7

 1 - 2sin2x + asinx - 2a - 7 = 0              cos2x = 1 - 2sin2x

 2sin2x - asinx - 8 + 2a = 0It is quadratic in sin x, so by using quadratic formula, we get sinx = a ± a2 - 4 × 22a - 8 /4on solving, we get sinx = a - 42

To find the possible values of a we will use the following inequation as we know that value of sin x lies between -1 to 1.

      - 1  a - 4/2  1 - 2  a - 4  2      2  a  6

So for this range the solution of the trigonometric equation exists


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82.

Find the values of x. - π < x < π, x  0 satisfying the equation,

g1 + cosx + cos2x + ...  = 43


83.

Prove that the centre of the smallest circle passing through origin and whose centre lies on y = x + 1 is - 12, 12


84.

Prove by induction that for n  N, n2 + n is an even integer (n  1)


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85.

If N = n!(n n  N, n > 2, then find

limNlog2N- 1 + log3N- 1 + ... + lognN- 1


86.

Use the formula limx0ax - 1x = logea to compute limx02x - 11 + x - 1


87.

If A, B are two square matrices such that AB = A and BA = B, then prove that B2 = B


88.

If dydx + 1 - y21 - x2 = 0 prove that, x1 - y2 + y1 - x2 = A where A is constant.


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89.

Evaluate the following integral

- 12xsinπxdx


90.

If f(a) = 2, f'(a) = 1, g(a) = - 1 and g'(a) = 2, find the value of limxagafa - gafxx - a


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