If y = Ax + Bx2, then x2d2ydx2 is equal to
2y
y2
y3
y4
A.
Given, y = Ax + Bx2
On differentiating, w.r.t. x, we get
dydx = - Ax2 + 2Bx
Again differentiating, we get
d2ydx2 = + 2Ax3 + 2B∴ x2d2ydx2 = 2Ax + 2Bx2 = 2y
The area enclosed between y2 = x and y = x is
23 sq unit
12 unit
13 unit
16
The area bounded by y2 = 4x and x = 4y is
203 sq units
163 sq units
143
103
The solution of dydx = yx + tanyx is
x = csinyx
x = csinxy
y = csinyx
xy = csinxy
Integrating Factor (IF) of the differential equation dydx - 3x2y1 + x3 = sin2x1 + x
e1 + x3
log1 + x3
1 + x3
11 + x3
The differential equation of y = aebx (a and b are parameters) is
yy1 = y22
yy2 = y12
yy12 = y2
yy22 = y1
The value of ∫0πsin50xcos49xdx is
0
π4
π2
1
∫2xf'(x) + f(x)log2dx is
2xf'(x) + C
2xf(x) + C
2x(log(2))f(x) + C
log(2)f(x) + C
Let fx = tan-1x. Then, f'(x) + f''(x) is 0, when x is equal to
i
- i
If y = tan-11 + x2x, then y'(1) is equal to
1/4
1/2
- 1/4
- 1/2