41.

The straight line passing through the point (1, 0, - 2) and perpendicular to the plane x - 2y + 5z - 7 = 0 is

• $\frac{\mathrm{x} - 1}{1} = \frac{\mathrm{y}}{0} = \frac{\mathrm{z} - 5}{- 2}$

• $\frac{\mathrm{x} - 1}{5} = \frac{\mathrm{y}}{- 2} = \frac{\mathrm{z} + 2}{1}$

• $\frac{\mathrm{x} - 5}{- 2} = \frac{\mathrm{y} - 1}{- 5} = \frac{\mathrm{z}}{1}$

• $\frac{\mathrm{x} - 1}{1} = \frac{\mathrm{y}}{- 2} = \frac{\mathrm{z} + 2}{5}$

The equation of the plane passing through (1, 2, 3) and parallel to 3x - 2y + 4z = 5 is

• 3x - 2y + 4z = 11

• 3x - 2y + 4z = 0

• 3x - 2y + 4z = 10

• 3(x - 1) - 2(y - 2) + 4(z - 3) = 5

If the straight lines $\frac{\mathrm{x} - 2}{1} = \frac{\mathrm{y} - 3}{1} = \frac{\mathrm{z} - 4}{0}$ and $\frac{\mathrm{x} - 1}{\mathrm{k}} = \frac{\mathrm{y} - 4}{2} = \frac{\mathrm{z} - 5}{1}$ are copalnar then, the value of k is

• - 3

• 0

• 1

• - 2

The line $\frac{\mathrm{x} - {\mathrm{x}}_1}{0} = \frac{\mathrm{y} - {\mathrm{y}}_1}{1} = \frac{\mathrm{z} - {\mathrm{z}}_1}{2}$ is

• perpendicular to the x-axis

• perpendicular to the yz-plane

• parallel to the y-axis

• parallel to the xz-plane