Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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71.

If dydx + 2xtanx - y = 1, then sinx - y = ?

  • Ae- x2

  • Ae2x

  • Aex2

  • Ae - 2x


C.

Aex2

Given differential equation isdydx + 2xtanx - y = 1Put x - y =t 1 - dydx = dtdx dydx =1 - dtdx 1 - dtdx + 2xtant = 1 dttant = 2xdx cottdt = 2xdxOn integrating both sides, we getlogsint = x2 + logA logsinx - y A = x2           sinx - y = Aex2


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72.

An integrating factor of the differential equation1 - x2dydx + xy = x41 + x51 - x23 is 

  • 1 - x2

  • x1 - x2

  • x21 - x2

  • 11 - x2


73.

Let A = 2e- 1i2012, C= ddx1xx = 1,D = e21dxx. If the sum of two roots of the equation  Ax3 + Bx2 + Cx - D = 0 is equal to zero, then B is equal to

  • - 1

  • 0

  • 1

  • 2


74.

a = i + j - 2k  a × i × j2 = ?

  • 6

  • 6

  • 36

  • 66


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75.

Let a, b and c be three non-coplanar vectors and let p, q and r be the vectors defined by

p = b × cabc, q = c × aabc,  r = a × babc Then,a + b . p + b + c . q + c + a . r = ?

  • 0

  • 1

  • 2

  • 3


76.

Let a = i + 2j + k, b = i - j + k, c = i + j - k.

A vector in the plane of a and b has projection 13 on c. Then, one such vector is

  • 4i + j - 4k

  • 3i + j - 3k

  • 4i - j + 4k

  • 2i + j + 2k


77.

The point if intersection of the lines

l1 : r(t) = (i - 6j + 2k) + t(i + 2j + k)

l: R(u) = (4j + k) + u(2i + j + 2k) is

  • (10, 12, 11)

  • (4, 4, 5)

  • (6, 4, 7)

  • (8, 8, 9)


78.

The vectors AB = 3i - 2j + 2k and BC = i - 2k are the adjacent sides of a parallelogram. The angle between its diagonals is

  • π2

  • π3 or 2π3

  • 3π4 or π4

  • None of these


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79.

Consider the circle x2 + y - 4x - 2y + c = 0 whose centre is A(2, 1). If the point P(10, 7) is such that the line segment PA meets the circle in Q with PQ = 5, then c is equal to

  • - 15

  • 20

  • 30

  • - 20


80.

A vertical pole subtends an angle tan-112 at a point P on the ground. If the angles substended by the upper half and the lower half of the pole at P are respectively α and β , then tanα, tanβ is equal to

  • 14, 15

  • 15, 29

  • 29, 14

  • 14, 29


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