Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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11.

The line joining two points A(2, 0), B(3, 1) is rotated about A in anti-clockwise direction through an angle of 15°. The equation of the line in the now position, is

  • √3x - y - 2√3 = 0

  • x - 3√y - 2 = 0

  • √3x + y - 2√3 = 0

  • x - √3y - 2 = 0


A.

√3x - y - 2√3 = 0

Here, slope of AB = 1/1

⇒ tan(0) = m1 = 1 or θ = 45°

Thus, slope of new line is tan(45° + 15°) = tan(60°) = √3
[∵ it is rotated anti-clockwise, so the angle will be 45° + 15° = 60°]

Hence, the equation is y = √3x + c, but it still passes through (2, 0), hence c = - 2√3.

Thus, required equation is

y = √3x - 2√3



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12.

The line 2x + 6y = 2 is a tanent to the curve x2 - 2y2 = 4. The point of contact is

  • 4, - 6

  • 7, - 26

  • (2, 3)

  • 6, 1


13.

The number of integral points (integral points means both the coordinates should be integer) exactly in the interior of the triangle with vertices (0, 0), (0, 21) and (21, 0) is

  • 133

  • 190

  • 233

  • 105


14.

If a tangent having slope of - 43 to the ellipse x218 + y232 = 1 intersects the major and minor axes in points A and B respectively, then the area of OAB is equal to (O is centre of the ellipse)

  • 12 sq units

  • 48 sq units

  • 64 sq units

  • 24 sq units


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15.

The locus of mid-points of tangents intercepted between the axes of ellipse x2a2 + y2b2 = 1 will be

  • a2x2 + b2y2 = 1

  • a2x2 + b2y2 = 2

  • a2x2 + b2y2 = 3

  • a2x2 + b2y2 = 4


16.

If PQ is a double ordinate of hyperbola (x2/a2) - (y2/b2) = 1 such that OPQ is a equilateral triangle, O being the centre of the hyperbola, then the eccentricity 'e' of the hyperbola satisfies

  • 1 < e < 2/√3

  • e = 2/√3

  • e = √3/2

  • e > 2/√3


17.

The sides AB, BC and CA of a ABC have respectively 3, 4 and 5 points lying on them. number of triangles that can be constructed using these points as vertices is

  • 205

  • 220

  • 210

  • None of these


18.

In the expansion of a + bxex, the coefficient of xr is

  • a - br!

  • a -brr!

  • - 1ra - brr!

  • None of the above


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19.

If n = (1999)!, Then x = 11999lognx is equal to

  • 1

  • 0

  • 19991999

  • - 1


20.

P is a fixed point (a, a, a) on a line through the origin is equally inclined to the axes, then any plane through P perpendicular to Op, makes intercepts on the axes, the sum of whose reciprocal is equal to

  • a

  • 32a

  • 3a2

  • None of these


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