Equation of the plane perpendicular to the line and passing through the point (2, 3, 4) is
2x + 3y + z = 17
x + 2y + 3z = 9
3x + 2y + z = 16
x + 2y + 3z = 20
D.
x + 2y + 3z = 20
Equation of plane passing through (2, 3, 4) is
a(x - 2) + b(y - 3) + c(z - 4) = 0 ...(i)
Since, above plane is perpendicular to the line
Thus, normal to the plane is parallel to the line
So, DR's of normal is (1, 2, 3),
i.e., (a, b, c) = (1, 2, 3)
Now, from Eq (i),
1(x - 2) + 2(y - 3) + 3(z - 4) = 0
The line is parallel to the plane
2x + 3y + 4z = 0
3x + 4y + 5z = 7
2x + y - 2z = 0
x + y + z = 2
If a and b are two unit vectors mclined at an angle then the value of is
equal to
greater than 1
equal to 0
less than 1