If the curves x2a2 + y2b2 = 1 and x225 + y216 = 1 cut each other orthogonally, then a2 - b2 = ?
9
400
75
41
A.
We know, two curves x2a2 + y2b2 = 1 and x225 + y216 = 1 cut orthogonallyThen, a12 - a22 = b12 - b22Here, equation of curves arex2a2 + y2b2 = 1 and x225 + y216 = 1 ∴ Condition of orthogonally,a2 - 25 = b2 - 16⇒ a2 - b2 = 25 - 16 = 9
The value of c in the Lagrange's mean value theorem for f(x) = x - 2 in the interval [2, 6] is
92
52
3
4
Te area (m sq units) of the region bounded by x = -1, x = 2, y = x2 + 1 and y = 2x - 2 is
10
7
8
If R is the set of all real numbers and f : R - {2} → R is defined by fx = 2 + x2 - x for x ∈ R - 2
R - {- 2}
R
R - {1}
R - {- 1}
Let Q be the set of all rational numbers in [0, 1]and f: [0, 1] → [0,1] be defined by
f(x) = x, for x ∈ Q1 - x for x∉ QThen, the set S = x ∈ 0, 21 : fofx = ?
[0, 1]
- Q
[0, 1] - Q
(0, 1)
∑k = 12n + 1- 1k - 1 . k2 = ?
(n - 1)(2n - 1)
(n + 1)(2n + 1)
(n + 1)(2n - 1)
(n - 1)(2n + 1)
If in the angles of a triangle are in the ratio1 : 1 : 4, then the ratio of the perimeter of the triangle to its largest side is
2 + 2 : 3
3 : 2
3 + 2 . 2
2 + 3 : 3
If in a ∆ABC, r1 = 2, r2 = 3 and 7a = 6, then ae quals to
1
2
The number of solutions for z3 + z = 0 , is
5
The least positive integer n for which (1 + i)n = (1 - i)n , is
6