Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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41.

For n = 4, using trapezoidal rule, the value of 02dx1 + x will be

  • 1.116625

  • 1.1176

  • 1.1180

  • None of these


A.

1.116625

Here, n = 4 and a = 0, b = 2 x = 2 - 04 = 12 = 0.5Now, y0 = fa = f0 = 11 + 0 = 1y1 = fa + x = f0 + 0.5     = f0.5 = 11 + 0.5 = 11.5 = 0.6666 y2 = fa + 2x = f0 + 2 × 0.5     = f1 = 11 + 1 = 12 = 0.5y3 = fa + 3x = f0 + 3 × 0.5     = f1 = 11 + 1.5 = 12.5 = 0.4y4 = fb = f1 = 11 + 2 = 13 = 0.33330211 + xdx = 0.512 + 0.6666 + 0.4 + 0.33332    = 0.50.5 + 0.66666 + 0.5 + 0.4 + 0.33332    = 0.50.5 + 0.6666 + 0.5 + 0.4 + 0.16665    = 0.5 × 2.23325 = 1.116625 (apporox.)


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42.

The value of 05dx1 + x2 by chosing six sub-intervals and by using Simpson's rule will be

  • 1.3562

  • 1.3662

  • 1.3456

  • 1.2662


43.

If G and G' are respectively centroid of ABC and A' B' C', then AA' + BB' + CC' is equal to

  • 2GG'

  • 3GG'

  • 23GG'

  • 13GG'


44.

If a = 3i^ - 4j^ + 5k^, b = i^ + j^ + k^ and c = - 2i^ + 3j^ - 5k^, and if [·] is the least integer function, then [a + b + c] is equal to

  • 1

  • 2

  • 3

  • 0


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45.

If a = - i^ + j^ + k^ and b = 2i^ + k^, then the vector satisfyin the following conditions

(i) it is coplanar witha and b,

(ii) it is perpendicular to b and

(iii) a · c = 7, is

  • - i^ + 2j^ + 2k^

  • - 32i^ + 52j^ + 3k^

  • - 3i^ + 5j^ + 6k^

  • - 6i^ + k^


46.

If the vectors b = tanα, - 1, 2sinα2 and c = tanα, tanα,  - 3sinα2 are orthagonal and  a vector a = 1, 3, sin2α makes an obtuse angle with the Z-axis, then the value of α is

  • 4n + 2π + tan-12

  • 4n + 2π - tan-12

  • 4n + 1π + tan-12

  • 4n + 1π - tan-12


47.

If cos4x + 1cotx - tanxdx = Acos4x + B, then the value of A is

  • 12

  • 18

  • - 18

  • 14


48.

If f(x) = fx = x, gx = ex - 1 and fogxdx = Afogx + Btan-1fogx + C, then the value of A + B is

  • 1

  • 2

  • 3

  • None of these


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49.

The value of 01tan-12x - 11 + x - x2dx is

  • 0

  • 1

  • - 1

  • None of these


50.

If 0 < P(A) < 1, 0 < P(B) < 1 and P(A  B) = P(A) + P(B) - P(A)P(B),then

  • PA  BC = PACPBC

  • P(A/B) = P(A)

  • Both (a) and (b) are  true

  • None of the above


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