Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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21.

The general solution of the equation dydx = y2 - x2yx + 1 is

  • y2 = (1 + x)log(1 + x) - c

  • y2 = 1 + xlogc1 - x - 1

  • y2 = 1 - xlogc1 - x - 1

  • y2 = 1 + xlogc1 + x - 1


D.

y2 = 1 + xlogc1 + x - 1

       dydx = y2 - x2yx + 1                             ...i ydydx = y2 - x2x + 1 ydydx - y22x + 1 = - x2x + 1     ...iiPut y2 = tBy differentiating both side w. r. t. 'x', we get 2ydydx = dtdx Eq. (ii) reduces to12dtdx - t2x + 1 = - x2x + 1This is linear differential equation withP = - 1x + 1 and Q = - xx + 1

 IF = ePdx         = e- 1x + 1dx        = e- logx + 1 = elog1x + 1        = 1x + 1Required solution will bet IF = QIFdx + logc     Here, logc is a constanty2 . 11 + x = - xx + 1 × 1x + 1dx + logc y21 + x = - x + 1 - 1x + 12dx + logc y21 + x = - 11 + xdx - 11 + x2dx + logc y21 + x = - log1 + x + 11 + x + logc y21 + x = logc1 + x - 11 + x        y2 = 1 + xlogc1 + x - 1


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22.

The general solution of the differential equation dydx + sinx + y2 = sinx - y2 is

  • logetany2 = - 2sinx2 +C

  • logetany4 = 2sinx2 +C

  • logetany2 = - 2sinx2 +C

  • logetany4 = - 2sinx2 +C


23.

If a, b, c are three vectors such that [a b c] = 5, then the value of [a x b, b x c, c x a] is

  • 15

  • 25

  • 20

  • 10


24.

The point of inflection of the function y = 0xt2 - 3t + 2dt is

  • 32, 34

  • - 32, - 34

  • - 12, - 32

  • 12, 32


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25.

The value of integral dxxx2 - a2

  • c - 1asin-1ax

  • c - 1acos-1ax

  • sin-1ax + c

  • c + 1asin-1ax


26.

The function y specified implicitly by the relation 0yetdt + 0xcostdt = 0 satisfies the differential equation

  • e2yd2ydx2 + dydx2 = sinx

  • eyd2ydx2 + dydx2 = sin2x

  • ey2d2ydx2 + dydx2 = sinx

  • eyd2ydx2 + dydx2 = sinx


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