Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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61.

If a non-zero vector a is parallel to the line of intersection of the plane determined by the vectors j^ - k^, 3j^ - 2k^ the plane determined by the vectors 2i^ + 3j^,  i ^- 3j^ then the angle between the vectors a and i^ + j^ + k^  is

  • sin-123

  • cos-1± 23

  • tan-13

  • cos-1 ± 13


D.

cos-1 ± 13

d Normal to plane P1 isn1 = j^ - k^ × 3j^ - 2k^ = i^j^k^01 - 103 - 2 = i^Normal to the plane P2 is n2 = [(2i^ +3j^) x (i^ - 3j^)= i^j^k^2301- 30 = i^0 - j^0 + k^ - 6 - 3= - 9kSince, a is parallel to the line of intersection of planes P1 and.P2, therefore a is parallel to ±( n1 x n2) i e a is parallel to 9j^ n1 × n2 = i^ × - 9k^= - 9i^ × k^ = 9j^Now, angle θ between 9j^ and i^ + j^ + k^ iscosθ = ± 993 = ± 13 θ = cos-1± 13


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62.

If three numbers are drawn at random successively without replacement from a set S = {1, 2, ... 10}, then the probability that the minimum of the chosen numbers is 3 or their maximum is 7

  • 1140

  • 540

  • 340

  • 140


63.

For x2 - 4  0, the value of ddxlogexx - 2x + 234 at x = 3 is

  • 85

  • 2

  • 1

  • 8e35


64.

If  y = sinh-1x1 + x2, then 1 + x2y2 + 3xy1 + y = ?

  • 2

  • 1

  •  - 1 

  • 0


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65.

5x + 3x2x2 - 2dx = ?

  •  32x + 1322log2 - x2 + x + C

  •  32x + 1342logx + 2x - 2 + C

  •  32x + 1342logx - 2x + 2 + C

  •  35x + 532logx + 2x - 2 + C


66.

If y = tan-1x1 + 1 - x2 + sin2tan-11 - x1 + x, then dydx = ?

  • 1 - 2x21 - x2

  • 1 - 2xx1 - x2

  • 2x + 1x1 - x

  • 2 - x21 - x2


67.

The equation of the plane through (4,4,0) and perpendicular to the planes 2x + y + 2z + 3 = 0 and 3x + 3y + 2z - 8 = 0

  • 4x + 3y + 3z = 28

  • 4x - 2y - 3z = 8

  • 4x + 2y + 3z = 24

  • 4x +2y - 3z = 24


68.

The solution of the equation

x - 4y3dydx - y = 0, y > 0 is

  • x = y3 + cy

  • x + 2y3 = cy

  • y = x3 + cx

  • y + 2x3 = cx


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69.

 If the points having the position vectors3i^ - 2j^ - k^, 2i + 3j^ - 4k^, - i^ + j^ + 2k^ and4i^ + 5j^ + λk^ are coplanar, then λ = ?

  • - 14617

  • 8

  •  - 8

  • 14617


70.

If 010fxdx= 5, then k = 11001fk - 1 + xdx = ?

  • 50

  • 10

  • 5

  • 20


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