11.

If Q(0, - 1, - 3) is the image  P in the plane 3x - y + 4z - 2 = 0 and R is the point (3, - 1, - 2). Then the area (in sq. units) of $△$PQR is :

• $\frac{\sqrt{91}}{4}$

• $\frac{\sqrt{91}}{2}$

• $2\sqrt{13}$

• $\frac{\sqrt{65}}{2}$