41.

Assertion : Al forms [AlF₆]^3- but B does not form [BF₆]^3-.

Reason : B does not react with fluorine.

• If both assertion and reason are true and reason is the correct explanation of assertion

• If both assertion and reason are true but reason is not the correct explanation of assertion

• If assertion is true but reason is false

• If both assertion and reason are false

Assertion : Cu(OH)₂ is soluble in NH₄OH but not in NaOH.

Reason : Cu(OH)₂ forms a soluble complex with NH₃.

• If both assertion and reason are true and reason is the correct explanation of assertion

• If both assertion and reason are true but reason is not the correct explanation of assertion

• If assertion is true but reason is false

• If both assertion and reason are false.

2-Phenylethylbromide when heated with NaOEt, elimination takes place. No deuterium exchange takes place when the reaction is carried out in C₂H₅OD solvent. The mechanism will be

• E1 elimination

• E2 elimination

• E1 cB elimination

• E2 or E1cB

Tincture of iodine is

• aqueous solution of I₂

• solution of I₂ in aqueous KI

• alcoholic solution of I₂

• aqueous solution of KI

Decreasing order of stability of ions is.
(i) CH₃ - $\stackrel{+}{\mathrm{C}}$H - CH₃

(ii) CH₃ - $\stackrel{+}{\mathrm{C}}$H - OCH₃

(iii) CH₃ - $\stackrel{+}{\mathrm{C}}$H - COCH₃

• (i) > (ii) > (iii)

• (ii) > (i) > (iii)

• (ii) > (iii) > (i)

• (iii) > (i) > (ii)

What is B ?

Formula of microcosmic salt is

• Na₂HPO₄

• Na(NH₄)HPO₄

• K₂HPO₄

• Na₂PO₄.K₂PO₄

Consider the reaction,

The correct explanation is

• the product is formed due to nucleophilic substitution

• the product is formed according to Saytzeff's rule

• conjugated double bond product is formed, due to higher stability because of resonance stabilization

• (CH₃)₃CO^- is a better leaving group

In solvents like DMSO, acetonitrile, F^- ion of dissolved NaF is more reactive than in methyl alcohol becasue

• CH₃OH is more polar than DMSO and CH₃CN

• CH₃OH is less polar than DMSO and CH₃CN

• unsolvated F^- ion is DMSO or CH₃CN acts more efficiently as nucleophile

• -OH group is a better leaving group than F^- ion