The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to
the speed of light in vacuum
the reciprocal of the speed of light in vacuum
the ratio of magnetic permeability to the electric susceptibility of vacuum
the ratio of magnetic permeability to the electric susceptibility of vacuum
B.
the reciprocal of the speed of light in vacuum
as E=cB
so the required ratio
Therefore, the ratio of the amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in a vacuum is equal to the reciprocal of the speed of light.
If the momentum of an electron is chagned by p, then the de-Broglie wavelenght associated with it changes by 0.5%. The initial momentum of electron will be
200p
400p
p/200
p/200
A proton carrying 1 MeV kinetic energy is moving in a circular path of radius R in the uniform magnetic field. What should be the energy of an alpha particle to describe a circle of the same radius in the same field.
2 MeV
1 MeV
0.5 MeV
0.5 MeV
For the angle of minimum deviation of a prism to be equal to its refracting angle, the prism must be made of a material whose refractive index
Lies between
Lies between 2 and
is less than 1
is less than 1
A rod of length 10 cm lies along the principal axis of a concave mirror of focal length 10 cm in such way that it end closer to pole is 20 cm away from the mirror. The length of the image is
10 cm
15 cm
2.5 cm
2.5 cm
Two radiations of photon energies 1 eV and 2.5 eV, successively illuminate a photosensitive metallic surface of the maximum speeds of the emitted electrons is
1:4
1:2
1:1
1:1
The transition from the state n = 3 to n=1 in a hydrogen-like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition from.
2→ 1
3 →2
4 → 2
4 → 2
The half-life to a radioactive nucleus is 50 days. The time interval (t2-t1) between the time t2 when 2/3 of it has decayed and the time t1 when 1/3 of it had decayed is
30 days
50 days
60 days
15 days
The Input resistance of silicon transistor 100Ω. Base current is changed by 40 uA which results in a change in collector current by 2 mA. This transistor is used as common-emitter amplifier with a load resistance of 4 kΩ. The voltage gain of the amplifier is
2000
3000
4000
4000
To get an output Y = 1 in given circuit which of the following input will be correct
A |
B |
C |
1 |
0 |
0 |
A |
B |
C |
1 |
0 |
1 |
A |
B |
C |
1 |
1 |
0 |
A |
B |
C |
1 |
1 |
0 |