Subject

Physics

Class

NEET Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

Advertisement

31.

Two metal wires of identical dimensions are connected in series if σ1a nd σ2 are the conductivity of the metal wires respectively, the conductivity of the combination is 

  • fraction numerator 2 straight sigma subscript 1 straight sigma subscript 2 over denominator straight sigma subscript 2 space plus straight sigma subscript 2 end fraction
  • fraction numerator straight sigma subscript 1 space plus straight sigma subscript 2 over denominator 2 space straight sigma subscript 1 straight sigma subscript 2 end fraction
  • fraction numerator straight sigma subscript 1 space plus straight sigma subscript 2 over denominator straight sigma subscript 1 straight sigma subscript 2 end fraction
  • fraction numerator straight sigma subscript 1 space plus straight sigma subscript 2 over denominator straight sigma subscript 1 straight sigma subscript 2 end fraction


A.

fraction numerator 2 straight sigma subscript 1 straight sigma subscript 2 over denominator straight sigma subscript 2 space plus straight sigma subscript 2 end fraction

Net resistance of a metal wire having resistivity rho,

we have

straight R subscript 1 space equals space straight rho subscript 1 straight L over straight A
similarly comma

straight R subscript 2 space equals space straight rho subscript 2 straight L over straight A
Then comma space net space effective space resistance space of space two space metal space wires.
straight R subscript eq space equals space straight R subscript 1 space plus straight R subscript 2
rightwards double arrow space straight rho fraction numerator 2 straight L over denominator straight A end fraction space equals space straight rho subscript 1 straight L over straight A space plus straight rho subscript 2 straight L over straight A

rightwards double arrow space 2 straight rho space equals space straight rho subscript 1 space plus straight rho subscript 2
As comma space conductivity space straight sigma space equals space 1 over straight rho comma space we space have
2 over straight sigma space equals space 1 over straight sigma subscript 1 space plus space 1 over straight sigma subscript 2

rightwards double arrow 2 over straight rho space equals space fraction numerator straight sigma subscript 1 plus straight sigma subscript 2 over denominator straight sigma subscript 1 straight sigma subscript 2 end fraction
rightwards double arrow space Net space effective space conductivity space of space combined space wires comma

straight sigma space equals space fraction numerator 2 straight sigma subscript 1 straight sigma subscript 2 over denominator straight sigma subscript 1 plus straight sigma subscript 2 end fraction

3220 Views

Advertisement
32.

A series R -C circuit is connected to an alternating voltage source. Consider tow situations:

1. When the capacitor is air filled.
2. When the capacitor is mica filled.

Current through resistor is i and voltage across capacitor is V then

  • Va < Vb

  • Va > Vb

  • ia >ib

  • ia >ib

971 Views

33.

A circuit contains an ammeter, a battery of 30 V and a resistance 40.8 Ω all connected in series. If the ammeter has a coil of resistance 480 Ω and a shunt 20 Ω then reading in the ammeter will be

  • 0.5 A

  • 0.25 A

  • 2 A

  • 2 A

852 Views

34.

An electron moves on a straight line path XY as shown. The abcd is a coil adjacent in the path of the electron. What will be the direction of the current, if any induced in the coil?

  • abcd

  • adcb

  • the current will reverse its direction as the electron goes past the coil

  • the current will reverse its direction as the electron goes past the coil

1402 Views

Advertisement
35.

A potentiometer wire of length L and a resistance r are connected in series with battery of e.m.f. Eo and a resistance r1. An unknown e.m.f is balanced at a length l of the potentiometer wire. The e.m.f E will be given by

  • fraction numerator LE subscript straight o straight r over denominator Ir subscript 1 end fraction
  • fraction numerator straight E subscript straight o straight r over denominator left parenthesis straight r space plus straight r subscript 1 right parenthesis end fraction. space I over L
  • fraction numerator straight E subscript straight o straight I over denominator straight L end fraction
  • fraction numerator straight E subscript straight o straight I over denominator straight L end fraction
2517 Views

36.

In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is 

  • 4/9

  • 9/4

  • 27/5

  • 27/5

1116 Views

37.

A photoelectric surface is illuminated successively by monochromatic light of wavelength λ and λ/2. If the maximum kinetic energy of the emitted photoelectrons in the second case is 3 times that in the first case, the work function of the surface of the material is 

(h = planck's constant, c= speed of light)

  • hc/ 2λ

  • hc/λ

  • 2 hc/λ

  • 2 hc/λ

1828 Views

38.

Light of wavelength 500 nm is incident on metal with work function 2.28 eV. The de - Broglie wavelength of the emitted electrons is 

  • <2.8 x 10-10

  • <2.8 x 10-9 m

  • > equal  to 2.8 x 10-9 m

  • > equal  to 2.8 x 10-9 m

2828 Views

Advertisement
39.

The input signal given to a CE amplifier having a voltage gain of 150 is straight V subscript straight i space equals space open parentheses 15 space straight t space plus space fraction numerator 2 straight pi over denominator 3 end fraction close parentheses The corresponding output signal will be

  • 300 space cos space open parentheses 15 space straight t space plus straight pi over 3 close parentheses
  • 75 space cos space open parentheses 15 space straight t space plus fraction numerator 2 straight pi over denominator 3 end fraction close parentheses
  • 2 space cos space open parentheses 15 space straight t space plus fraction numerator 5 straight pi over denominator 3 end fraction close parentheses
  • 2 space cos space open parentheses 15 space straight t space plus fraction numerator 5 straight pi over denominator 3 end fraction close parentheses
1178 Views

40.

A nucleus of uranium decays at rest into nuclei of thorium and helium. Then, 

  • the helium nucleus has more kinetic energy than the thorium nucleus

  • the helium nucleus has less momentum than the thorium nucleus

  • the helium nucleus has more momentum than the thorium nucleus

  • the helium nucleus has more momentum than the thorium nucleus

701 Views

Advertisement