Short Answer Type
Long Answer TypeAn organic compound A’ having molecular formula C2H5O2N reacts with HNO2 and gives C2H4O3N2. On reduction A’ gives a compound ‘B’ with molecular formula C2H7N.C’on treatment with HNO2 gives C’ which givespositive idoform test . Identify A,B,C.
Out of acetophenone and benzophenone, which gives iodoform test ? Write the reaction involved. (The compound should have CH3CO-group to show the iodoform test.)
Short Answer TypeGive simple chemical tests to distinguish between the following pairs of compounds:
(i) Benzaldehyde and Benzoic acid
(ii) Propanal and Propanone
Benzaldehyde and Benzoic acid
Test-1 Through sodium bicarbonate Benzaldehyde does not react with sodium bicarbonate. However, benzoic acid will produce brisk effervescence on reaction with sodium bicarbonate as shown in the given reaction:
C6H5COOH + NaHCO3 ---> C6H5COONa + H2O + CO2
Test-2 Through, Tollen's reagent Benzaldehyde reacts with an ammoniacal solution of silver nitrate to form a silver mirror.
C6H5CHO + 2[Ag(NH3)2]+ + 3OH- --> C6H5COO- + 2Ag + 2H2O + 4NH3
However, no such reaction is given by benzoic acid.
(ii) Test-1 Iodoform Test
Propanone gives positive iodoform test, as it contains CH3CO group, whereas propanal does not give iodoform test. The reaction is as follows:
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