Short Answer TypeGive reasons for the following observations:
It is necessary to remove CO when ammonia is prepared by Haber's process.
Account for the following:
(i) Acidic character increases from HF to HI.
(ii) There is a large difference between the melting and boiling points of oxygen and sulphur.
(iii) Nitrogen does not form pentahalide.
(i) The acidic strength of the hydrohalic acids increases from HF to HI because the stability of the acids decreases from HF to HI on account of decrease in bond dissociation enthalpy of H-X bond from HF to HI.
(ii) The oxygen exists as a diatomic molecule, O2, while sulphur exists as a polyatomic molecule, S8. Hence, there is a large difference between the melting point and the boiling point of oxygen and sulphur.
(iii) Group 15 elements form pentahalides when they have empty d-orbitals, which are can be used for forming coordinate bonds. Since nitrogen does not have d-orbitals, it cannot form petahalides.
Long Answer Type(i) Which allotrope of phosphorus is more reactive and why?
(ii) How the supersonic jet aeroplanes are responsible for the depletion of ozone layers?
(iii) F2 has lower bond dissociation enthalpy than Cl2. Why?
(iv) Which noble gas is used in filling balloons for meteorological observations?
(v) Complete the equation: XeF2 + PF5 →
Short Answer TypeComplete the following chemical equations:
(i) Ca3P2 + H2O -->
(ii) Cu + H2SO4(conc.)-->
Arrange the following in the order of the property indicated by each set:
(i) HF, HCl, HBr, HI - increasing bond dissociation enthalpy.
(ii) H2O, H2S, H2Se, H2Te- increasing acidic character.
Account for the following:
(i) PCl5 is more covalent than PCl3.
(ii) Iron on reaction with HCl forms FeCl2 and not FeCl3.
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