Show that the height of the cylinder of maximum volume that can be inscribed in a cone of height h is h.
A tank with rectangular base and rectangular sides, open at the top is to be constructed so that its depth is 2 m and volume is 8 m³. If building of tank costs Rs. 70 per square metre for the base and Rs. 45 per square metre for sides, what is the cost of least expensive tank?
Let l, b, and h denote the length breadth and depth of the open rectangular tank.
Given h = 2m
V = 8m3
i.e. 2 l b= 8
Surface area, S, of the open rectangular tank of the depth 'h' = l b + 2( l + b ) x h
In this problem, b = , l b = 4 metre, h = 2 metre
For maxima or minima, differentiating with respect to l we get,
l = 2m for minimum 0r maximum
= 4 + 2 x 8 = 4 + 16 = 20 square metres
Base Area = 4 square metres; Lateral surface area = 16 square metres
Cost = 4 x 70 + 16 x 45
= 280 + 720
= Rs. 1000.
Find the equations of the normals to the curve y = x3 + 2x + 6 which are parallel to the line x + 14y + 4 = 0.
Find the values of x for which f(x) = [x(x - 2)]2 is an increasing function. Also, find the points on the curve where the tangent is parallel to x-axis.
Show that the right circular cylinder, open at the top, and of given surface area and maximum volume is such that its height is equal to the radius of the base.