The two circles x2 + y2 = ax and x2 + y2 = c2(c > 0) touch ea

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441.

A wire of length 2 units is cut into two parts which are bent respectively to form a square of side=x units and a circle of radius=r units. If the sum of the areas of the square and the circle so formed is minimum, then:

  • 2x=(π+4)r

  • (4−π)x=πr

  • x=2r

  • x=2r

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442.

Let f (x) be a polynomial of degree four having extreme values at x =1 an x =2. If limit as straight x rightwards arrow 0 of open square brackets 1 plus fraction numerator straight f left parenthesis straight x right parenthesis over denominator straight x squared end fraction close square brackets space equals space 3 comma then f(2) is equal to 

  • -8

  • -4

  • 0

  • 0

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443.

A spherical balloon is filled with 4500π cubic meters of helium gas. If a leak in the balloon causes the gas to escape at the rate of 72π cubic meters per minute, then the rate (in meters per minute) at which the radius of the balloon decreases 49 minutes after the leakage began is

  • 9/7

  • 7/9

  • 2/9

  • 2/9

1221 Views

444.

Let a, b ∈ R be such that the function f given by f(x) = ln |x| + bx
2+ ax, x ≠ 0 has extreme values at x = –1 and x = 2.
Statement 1: f has local maximum at x = –1 and at x = 2.
Statement 2: straight a space equals space 1 half space and space straight b space equals space fraction numerator negative 1 over denominator 4 end fraction

  • Statement 1 is false, statement 2 is true

  • Statement 1 is true, statement 2 is true; statement 2 is a correct explanation for statement 1

  • Statement 1 is true, statement 2 is true; statement 2 is not a correct explanation for statement 1

  • Statement 1 is true, statement 2 is true; statement 2 is not a correct explanation for statement 1

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445.

If dy/dx = y + 3 > 0 and y(0) = 2, then y(ln2) is equal to:

  • 7

  • 5

  • 13

  • 13

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446.

Equation of the ellipse whose axes are the axes of coordinates and which passes through the point (-3, 1) and has eccentricity square root of 2 over 5 end root is

  • 3x2 + 5y2 -32 = 0

  • 5x2 + 3y2 - 48 = 0

  • 3x2 + 5y2 - 15 = 0 

  • 3x2 + 5y2 - 15 = 0 

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447.

The two circles x2 + y2 = ax and x2 + y2 = c2(c > 0) touch each other if

  • 2|a| = c

  • |a| = c

  • a = 2c

  • a = 2c


B.

|a| = c

x2 + y2 = ax ...........(1)

rightwards double arrow space Centre space straight c subscript 1 space open parentheses negative straight a over 2 comma 0 close parentheses space and space radius space straight r subscript 1 space equals space open vertical bar straight a over 2 close vertical bar
straight x squared space plus space straight y squared space equals space straight c squared space.... space left parenthesis 2 right parenthesis
rightwards double arrow space Centre space straight c subscript 2 space left parenthesis 0 comma 0 right parenthesis space and space radius space straight r subscript 2 space equals straight c
both space touch space each space other space iff
vertical line straight c subscript 1 straight c subscript 2 vertical line space equals space straight r subscript 1 space plus-or-minus space straight r subscript 2
straight a squared over 4 space equals space open parentheses plus-or-minus straight a over 2 plus-or-minus straight c close parentheses squared
rightwards double arrow space straight a squared over 4 space equals space straight a squared over 4 space plus-or-minus space vertical line straight a vertical line space straight c space plus straight c squared
rightwards double arrow vertical line straight a vertical line space equals space straight c
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448.

If two tangents drawn from a point P to the parabola y2= 4x are at right angles, then the locus of P is

  • X = 1

  • 2x +1 = 0

  • x = -1

  • x = -1

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449.

The radius of a circle, having minimum area, which touches the curve y = 4 – x2 and the lines, y = |x| is

  • 4 space left parenthesis square root of 2 space plus 1 right parenthesis
  • 2 left parenthesis square root of 2 space plus 1 right parenthesis
  • 2 left parenthesis square root of 2 space minus 1 right parenthesis
  • 2 left parenthesis square root of 2 space minus 1 right parenthesis
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450.

Let y be an implicit function of x defined by x2x – 2xxcoty – 1 = 0. Then y′ (1) equals 

  • -1

  • 1

  • log 2

  • log 2

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