The eccentricity of an ellipse whose centre is at the origin is

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201.

The area bounded between the parabolas x2=y/4 and x2 = 9y, and the straight line y = 2 is

  • 20 square root of 2
  • fraction numerator 10 space square root of 2 over denominator 3 end fraction
  • fraction numerator 20 space square root of 2 over denominator 3 end fraction
  • fraction numerator 20 space square root of 2 over denominator 3 end fraction
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202.

If z ≠ 1 and fraction numerator straight z squared over denominator straight z minus 1 end fraction is real, then the point represented by the complex number z lies

  • either on the real axis or on a circle passing through the origin

  • on a circle with centre at the origin

  • either on the real axis or on a circle not passing through the origin

  • either on the real axis or on a circle not passing through the origin

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203.

The length of the diameter of the circle which touches the x-axis at the point (1, 0) and passes through the point (2, 3) is

  • 10/3

  • 3/5

  • 6/5

  • 6/5

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204.

An ellipse is drawn by taking a diameter of the circle (x–1)2 + y2 = 1 as its semiminor axis and a diameter of the circle x2 + (y – 2)2 = 4 as its semi-major axis. If the centre of the ellipse is the origin and its axes are the coordinate axes, then the equation of the ellipse is

  • 4x2+ y2 = 4

  • x2 +4y2 =8

  • 4x2 +y2 =8

  • 4x2 +y2 =8

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205.

For a regular polygon, let r and R be the radii of the inscribed and the circumscribed circles. A false statement among the following is

  • there is a regular polygon with r/R = 1/2

  • there is a regular polygon with straight r over straight R space equals space fraction numerator 1 over denominator square root of 2 end fraction

  • there is a regular polygon with r/R = 2/3

  • there is a regular polygon with r/R = 2/3

190 Views

206.

hyperbola passes through the point P(√2, √3) and has foci at (± 2, 0). Then the tangent to this hyperbola at P also passes through the point

  • left parenthesis negative square root of 2 comma space minus square root of 3 right parenthesis
  • left parenthesis 3 square root of 2 space comma space 2 square root of 3 right parenthesis
  • left parenthesis 2 square root of 2 space comma 3 space square root of 3 right parenthesis
  • left parenthesis 2 square root of 2 space comma 3 space square root of 3 right parenthesis
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207.

The eccentricity of an ellipse whose centre is at the origin is 1/2. If one of its directives is x= –4, then the equation of the normal to it at (1,3/2) is

  • x + 2y = 4

  • 2y – x = 2

  • 4x – 2y = 1

  • 4x – 2y = 1


C.

4x – 2y = 1

Eccentricity of ellipse =1/2



Now, a/e = -4
⇒ a = 4 x (1/2) = 2
therefore, b2 = a2(1-e2)
= a2 (1-(1/4)) = 3
straight x squared over 4 space plus space straight y squared over 3 space equals space 1
rightwards double arrow space straight x over 2 space plus space fraction numerator 2 straight y over denominator 3 end fraction space straight x space straight y apostrophe space equals space 0
rightwards double arrow space straight y apostrophe space equals space minus fraction numerator 3 straight x over denominator 4 straight y end fraction
straight y apostrophe vertical line subscript left parenthesis 1 comma space 3 divided by 2 right parenthesis end subscript space equals space minus 3 over 4 space straight x 2 over 3 space equals space minus 1 half

Equation of normal at (1, 3/2)
y-3/2 = 2(x – 1)
⇒ 2y – 3 = 4x – 4
⇒ 4x – 2y = 1

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208.

The ellipse x2+ 4y2= 4 is inscribed in a rectangle aligned with the coordinate axes, which in turn is inscribed in another ellipse that passes through the point (4, 0). Then the equation of the ellipse is

  • x2+ 16y2= 16 

  • x2+ 12y2= 16 

  • 4x2+ 48y2= 48 

  • 4x2+ 48y2= 48 

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209.

A focus of an ellipse is at the origin. The directrix is the line x = 4 and the eccentricity is 1/2. Then the length of the semi−major axis is 

  • 8/3

  • 2/3

  • 5/3

  • 5/3

737 Views

210.

A parabola has the origin as its focus and the line x = 2 as the directrix. Then the vertex of the parabola is at 

  • (0, 2)

  • (1, 0)

  • (0,1)

  • (0,1)

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