An ellipse has OB as semi-minor axis, F and F′ its focii and t

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 Multiple Choice QuestionsMultiple Choice Questions

221.

Let P be the point (1, 0) and Q a point on the locus y2 = 8x. The locus of mid point of PQ is

  • y2 – 4x + 2 = 0

  • y2 + 4x + 2 = 0

  • x2 + 4y + 2 =

  • x2 + 4y + 2 =

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222. If space straight omega space equals space fraction numerator straight z over denominator straight z minus begin display style 1 third end style straight i space end fraction space and space vertical line straight omega vertical line space equals 1 comma space then space straight z space lies space on
  • an ellipse

  • a circle

  • a straight line

  • a straight line

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223.

The locus of a point P (α, β) moving under the condition that the line y = αx + β is a tangent to the hyperbola straight x squared over straight a squared space minus straight y squared over straight b squared space equals space 1 space is

  • an ellipse

  • a circle

  • a parabola

  • a parabola

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224.

If the circles x2 + y2 + 2ax + cy + a = 0 and x2 + y2 – 3ax + dy – 1 = 0 intersect in two distinct points P and Q then the line 5x + by – a = 0 passes through P and Q for

  • exactly one value of a

  • no value of a

  • infinitely many values of a

  • infinitely many values of a

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225.

A circle touches the x-axis and also touches the circle with centre at (0, 3) and radius 2. The locus of the centre of the circle is 

  • an ellipse

  • a circle

  • a hyperbola

  • a hyperbola

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226.

If a circle passes through the point (a, b) and cuts the circle x2 + y2 = p2 orthogonally, then the equation of the locus of its centre is 

  • x2 + y2 – 3ax – 4by + (a2 + b2 – p2 ) = 0

  • 2ax + 2by – (a2 – b2 + p2 ) = 0

  • x2 + y2 – 2ax – 3by + (a2 – b2 – p2 ) = 0

  • x2 + y2 – 2ax – 3by + (a2 – b2 – p2 ) = 0

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227.

An ellipse has OB as semi-minor axis, F and F′ its focii and the angle FBF′ is a right angle. Then the eccentricity of the ellipse is

  • fraction numerator 1 over denominator square root of 2 end fraction
  • 1/2

  • 1/4

  • 1/4


A.

fraction numerator 1 over denominator square root of 2 end fraction


therefore space angle space FBF apostrophe space equals 90 to the power of 0
therefore space left parenthesis square root of straight a squared straight e squared plus straight b squared end root right parenthesis squared space plus space open parentheses square root of straight a squared straight e squared plus straight b squared end root close parentheses squared space equals left parenthesis 2 ae right parenthesis squared
rightwards double arrow space 2 left parenthesis straight a squared space straight e squared space plus straight b squared right parenthesis space equals 4 straight a squared straight e squared
rightwards double arrow straight e squared space equals space straight b squared divided by straight a squared
also space straight e squared space equals space 1 minus straight b squared divided by straight a squared space equals space 1 minus straight e squared
rightwards double arrow 2 straight e squared space equals 1 comma space straight e space equals space fraction numerator 1 over denominator square root of 2 end fraction
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228.

If the pair of lines ax2 + 2(a + b)xy + by2 = 0 lie along diameters of a circle and divide the circle into four sectors such that the area of one of the sectors is thrice the area of another sector then

  • 3a2 – 10ab + 3b2 = 0

  • 3a2 – 2ab + 3b2 = 0

  • 3a2 + 10ab + 3b2 = 0

  • 3a2 + 10ab + 3b2 = 0

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229.

If |z2-1|=|z|2+1, then z lies on

  • the real axis

  • an ellipse

  • a circle

  • a circle

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230.

If a circle passes through the point (a, b) and cuts the circle x2 +y2= 4 orthogonally, then the locus of its centre is

  • 2ax +2by + (a2 +b2+4)=0

  • 2ax +2by - (a2 +b2+4)=0

  • 2ax -2by - (a2 +b2+4)=0

  • 2ax -2by - (a2 +b2+4)=0

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