Let the foci of the ellipse x29 + y2 = 1

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 Multiple Choice QuestionsMultiple Choice Questions

281.

The line y = x intersects the hyperbola x29 - y225 = 1 at the points P and Q. The eccentricity of ellipse with PQ as major axis and minor axis of length 52 is

  • 53

  • 53

  • 59

  • 229


282.

If the distance between the foci of an ellipse is equal to the length of the latusrectum, then its eccentricity is

  • 145 - 1

  • 125 + 1

  • 125 - 1

  • 145 + 1


283.

The equation of the circle passing through the point (1, 1) and the points of intersection of x2 + y2 -  6x - 8 = 0 and x2 + y2 - 6 = 0 is 

  • x2 + y2 + 3x - 5 = 0

  • x2 + y2 - 4x + 2 = 0

  • x2 + y2 + 6x - 4 = 0

  • x2 + y2 - 4y - 2 = 0


284.

The area of the region bounded by the parabola y = x2 - 4x + 5 and the straight line y= x + l is

  • 12

  • 2

  • 3

  • 92


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285.

If P be a point on the parabola y = 4ax with focus F. Let Q denote the foot of the perpendicular from P onto the directrix. Then, tanPQFtanPFQ is

  • 1

  • 12

  • 2

  • 14


286.

The equations of the circles, which touch both the axes and the line 4x + 3y = 12 and have centres in the first quadrant, are

  • x2 + y2 + x - y + 1 = 0

  • x2 + y2 - 2x - 2y + 1 = 0

  • x2 + y2 - 12x - 12y + 36 = 0

  • x2 + y2 - 6x - 6y + 36 = 0


287.

The equation y2 + 4x + 4y + k = 0 represents a parabola whose latusrectum is

  • 1

  • 2

  • 3

  • 4


288.

If the circles x2 + y2 + 2x + 2ky + 6 = 0 and x2 + y+ 2ky + k = 0 intersect orthogonally, then k is equal to

 

  • 2 or - 32

  • - 2 or - 32

  • 2 or  32

  • - 2 or  32


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289.

If four distinct points (2k, 3k), (2, 0), (0, 3), (0, 0) lie on a circle, then

  • k < 0

  • 0 < k < 1

  • k = 1

  • k > 1


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290.

Let the foci of the ellipse x29 + y2 = 1 subtend a right angle at a point P. Then, the locus of P is

  • x2 + y2 = 1

  • x2 + y2 = 2

  • x2 + y2 = 4

  • x2 + y2 = 8


D.

x2 + y2 = 8

x29 + y21 = 1        e = 1 - 19               = 223

Two foci are (± ae, 0) i.e., (± 22, 0)

Let P(h, k) by any point on the ellipse

 k - 0h - 22 × k - 0h + 22 = - 1

               From given condition

  h2 - 8 = - k2 x2 + y2 = 8


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