Let y be the solution of the differential equation
satisfying y(1) = 1. Then, y satisfies
y = xy - 1
y = xy
y = xy + 1
y = xy + 2
The general solution of the differential equation
is
(A + B)e5x
(A + Bx)e- 4x
(A + Bx2)e4x
(A + Bx4)e4x
If x2 + y2 = 4, then is equal to
4
0
1
- 1
B.
0
Given, x2 + y2 = 4
On differentiating w.r.t. x, we get
2x + 2y = 0
The general solution of the differential equation is
ex + e- y = C
ex + ey = C
ey + e- x = C
e- x + e- y = C