∫sinθ + cosθsin2θdθ is

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

631.

If I1sin-1xdx and I2sin-11 - x2dx, then

  • I1 = I2

  • I2 = π2I1

  • I1 + I2 = π2x

  • I1 + I2 = π2


Advertisement

632.

sinθ + cosθsin2θ is equal to

  • logcosθ - sinθ + sin2θ + c

  • logsinθ - cosθ + sin2θ + c

  • sin-1sinθ - cosθ + c

  • sin-1sinθ + cosθ + c


C.

sin-1sinθ - cosθ + c

Let I = sinθ + cosθ1 +sin2θ - 1       = sinθ + cosθ1 - sinθ - cosθ2Put sinθ - cosθ = t cosθ + sinθ = dt I = 11 - t2dt = sin-1t + c      = sin-1sinθ - cosθ + c


Advertisement
633.

π6π3dx1 + tanx is equal to

  • π12

  • π2

  • π6

  • π4


634.

If f is a continuous function, then

  • - 22f(x)dx = 02f(x) - f(- x)dx

  • - 352f(x)dx = - 610fx - 1dx

  • - 35fxdx = - 44fx - 1dx

  • - 35fxdx = - 26fx - 1dx


Advertisement
635.

1 + sinx1 + cosxdx is equal to

  • xtanx2 + c

  • log1 + cosx +c

  • cotx2 +c

  • logx + sinx +c


636.

cos3x . elogsinxdx is equal to

  • - sin4x4 + c

  • - cos4x4 + c

  • esinx4 +c

  • None of the above


637.

The value of 0π2cos3x + 12cosx - 1dx is

  • 2

  • 1

  • 12

  • 0


638.

The value of 01tan-12x - 11 + x - x2dx is

  • 1

  • 0

  • - 1

  • None of the above


Advertisement
639.

By the application of Simpson's one - third rule for numerical integration, with two subintervals, the value of 01dx1 +x is

  • 1736

  • 1725

  • 2536

  • 1724


640.

xe - 1 + ex - 1xe + exdx is equal to

  • logxe + ex +c

  • elogxe + ex +c

  • 1elogxe + ex +c

  • None of the above


Advertisement