If I1 = I1 = ∫0π2sinxdx and I2&nb

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 Multiple Choice QuestionsMultiple Choice Questions

761.

0π4log1 + tanxdx is equal to

  • π8loge2

  • π4log2e

  • π4loge2

  • π8loge12


762.

x3 +3x2 + 3x + 1x + 15dx is equal to

  • - 1x + 1 +c

  • 15logx +1 + c

  • logx + 1 +c

  • tan-1x +c


763.

cscxcos21 + logtanx2dx is equal to :

  • sin21 + logtanx2 + c

  • tan1 + logtanx2 + c

  • sec21 + logtanx2 + c

  • - tan1 + logtanx2 + c


764.

dxxx6 - 16 is equa to :

  • 13sec-1x34 +c

  • cosh-1x34 +c

  • 112sec-1x34 +c

  • sec-1x34 +c


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765.

If I1I1 = 0π2sinxdx and I2 = 0π2xcosxdx, then which one of the following is true ?

  • I1 + I2 = π2

  • I2 - I1= π2

  • I1 + I2 = 0

  • I1 = I2 


B.

I2 - I1= π2

Since, I1 = 0π2sinxdxand     I2 = 0π2xcosxdx I1 = xcosx0π2 - 0π2cosxdx        = 0 - 0 + sinx0π2        = 1and I2 = 0π2xcosxdx         = xsinx0π2 - 0π2cosxdx         = π2 - 0 + sinx0π2         = π2 +1From (i) and (ii), we get      I2 - I1= π2


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766.

If f(x) is defined [- 2, 2] by f(x) = 4 - 3x + 1 and g(x) = f- x - fxx2 + 3, then - 22gxdx is equal to :

  • 64

  • - 48

  • 0

  • 24


767.

The value of the integral 0π2sin100x - cos100xdx is

  • 1100

  • 100!100100

  • π100

  • 0


768.

If k01x . f3xdx = 03t . ftdt, then the value of k is

  • 9

  • 3

  • 19

  • 13


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769.

The value of 11 + cos8xdx is

  • tan2x8 + c

  • tan8x8 + c

  • tan4x4 + c

  • tan4x8 + c


770.

The value of exx5 + 5x4 + 1dx is

  • ex . x5 + c

  • e. x5 + e+ c

  • ex + 1 . x5 + c

  • 5x4 . ex + c


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