∫cos2x - cos2θcosx - cosθdx&n

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

811.

The value of e6logx - e5logxe4logx - e3logxdx is equal to

  • 0 + C

  • x33 + C

  • 3x3 + C

  • 1x + C


812.

0π2sin1000xsin1000x + cos1000xdx is equal to

  • 1000

  • 1

  • π2

  • π4


813.

The vaue of 2810 - xx + 10 - xdx is

  • 10

  • 0

  • 8

  • 3


814.

- π2π2dxesinx + 1

  • 1

  • 0

  • π2

  • - π2


Advertisement
815.

- 55x + 2dx is equal to

  • 28

  • 30

  • 29

  • 27


816.

0π21a2 . sin2x +b2 . cos2xdx

  • π2ab

  • πb4a

  • πa2b

  • πa4b


817.

x2 + 2x + 5dx is equal to

  • 12x + 1x2 + 2x + 5 + 2logx + 1 + x2 + 2x + 5 + C

  • x + 1x2 + 2x + 5 + 12logx + 1 + x2 + 2x + 5 + C

  • x + 1x2 + 2x + 5 + 2logx + 1 + x2 + 2x + 5 + C

  • x + 1x2 + 2x + 5 - 2logx + 1 + x2 + 2x + 5 + C


818.

x + 3exx + 42dx is equal to

  • exx + 42 + C

  • exx + 3 + C

  • 1x + 42 + C

  • exx + 4 + C


Advertisement
Advertisement

819.

cos2x - cos2θcosx - cosθdx is equal to

  • 2sinx + xcosθ

  • 2sinx - xcosθ

  • 2sinx + 2xcosθ

  • 2sinx - 2xcosθ


A.

2sinx + xcosθ

Let I = cos2x - cos2θcosx - cosθdx= 2cos2x - 1 - 2cos2θ - 1cosx - cosθdx= 2cos2x - cos2θcosx - cosθdx= 2cosx - cosθcosx - cosθcosx - cosθdx= 2cosx + cosθ= 2sinx + xcosθ + C


Advertisement
820.

0.23.5xdx is equal to

  • 3.5

  • 4

  • 4.5

  • 3


Advertisement