∫dxa2sin2x + b2cos2x is equal to from Mathema

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 Multiple Choice QuestionsMultiple Choice Questions

901.

Evaluate - 21fxdx, where f(x) = 1 - 2x, x  01 + 2x, x  0

  • 0

  • 2

  • 4

  • 6


902.

dxxx +9 is equal to

  • 23tan-1x + C

  • 23tan-1x3 + C

  • tan-1x + C

  • tan-1x3 + C


903.

x + 12exdx is equal to

  • xex + C

  • x2xx + C

  • (x + 1)ex + C

  • (x2 + 1)ex + C


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904.

dxa2sin2x + b2cos2x is equal to

  • 1abtan-1atanxb + C

  • tan-1atanxb + C

  • 1abtan-1btanxa + C

  • tan-1btanxa + C


A.

1abtan-1atanxb + C

dxa2sin2x + b2cos2x   = 1a2sec2xdxba2 + tan2x    = 1abtan-1atanxb + C


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905.

0π2sin8xcos2xdx is equal to

  • π512

  • 3π512

  • 5π512

  • 7π512


906.

- 11ax3 + bxdx = 0 for

  • any value of a and b

  • a > 0, b > 0 only

  • a > 0, b > 0 only

  • a < 0, b > 0 only


907.

Using the Trapezoidal rule, the approximate value of 14ydx
x 1 2 3 4
y 0.7111 0.7222 0.7333 0.7444

 

  • 0.1833

  • 1.1833

  • 2.1833

  • 3.1833


908.

dx1 - cosx  - sinx is equal to

  • log1 + cotx2 + c

  • log1 -  tanx2 + c

  • log1 - cotx2 + c

  • log1 + tanx2 + c


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909.

dx7 + 5cosx is equal to

  • 13tan-113tanx2 + c

  • 16tan-116tanx2 + c

  • 17tan-1tanx2 + c

  • 14tan -1tanx2 + c


910.

3xdx9x - 1 is equal to

  • 1log3log3x + 9x - 1 + c

  • 1log3log3x - 9x - 1 + c

  • 1log9log3x + 9x - 1 + c

  • 1log3log9x + 9x - 1 + c


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