Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

Advertisement
91.

If logex2 - 16  loge4x - 11, then

  • 4 < x  5

  • x < - 4 or x > 4

  • - 1 < x  5

  • x < - 1 or x > 5


 Multiple Choice QuestionsShort Answer Type

92.

Determine the sum of imaginary roots of the equation (2x + x - 1) ( 4x2 + 2x - 3) = 6


 Multiple Choice QuestionsMultiple Choice Questions

93.

Let a, b, c be three real numbers, such that a + 2b + 4c = 0, Then, the equation ax2 + bx + c = 0

  • has both the roots complex

  • has its roots lying within - 1 < x < 0

  • has one of roots equal to 12

  • has its roots lying within 2 < x < 6


94.

If the ratio of the roots of the equation px+ qx + r = 0 is a : b, then aba + b2

  • p2qr

  • prq2

  • q2pr

  • pqr2


Advertisement
95.

If α and β  are the roots of the equation x2 + x + 1 = 0, then the equation whose roots are α19 and β7 is

  • x2 - x - 1 = 0

  • x2 - x + 1 = 0

  • x2 + x - 1 = 0

  • x2 + x + 1 = 0


96.

For the real parameter t, the locus of the complex number z = 1 - t2 + i1 + t2 in the complex plane is

  • an ellipse

  • a parabola

  • a circle

  • a hyperbola


97.

If α, β be the roots of the quadratic equation x2 + x + 1 = 0, then the equation whose roots are α19. β7 f is

  • x2 - x + 1 = 0

  • x2 - x - 1 = 0

  • x2 + x - 1 = 0

  • x2 + x + 1 = 0


98.

The roots of the quadratic equation x2 - 23x - 22 = 0 are

  • imaginary

  • real, rational and equal

  • real, irrational and unequal

  • real, rational and unequal


Advertisement
99.

The quadratic equation x2 + 15x + 14 = 0 has

  • only positive solutions

  • only negative solutions

  • no solution

  • both positive and negative solution


100.

If z = 41 - i, then z¯ is (where z¯ is complex conjugate of z)

  • 2(1 + i)

  • (1 + i)

  • 21 - i

  • 41 + i


Advertisement