(CH3)3COCH3 and CH3OC2H5 are treated with hydroiodic acid. The fr

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 Multiple Choice QuestionsMultiple Choice Questions

341.

What is the name of reaction when benzaldehyde changes in to benzyl alcohol?

  • Cannizzaro's reaction

  • Wurtz reaction

  • Kolbe reaction

  • Friedel-Craft's reaction


342.

Gammexane is

  • benzene hexachloride

  • bromo benzene

  • benzyl chloride

  • chlorobenzene


343.

Aniline on treatment with HCl and NaNO2 gives

  • diazo salt

  • nitroaniline

  • chloroaniline

  • aminophenol


344.

Dehydration of alcohol involves

  • carbene

  • carbanion

  • free radical

  • carbonium ion


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345.

A sample of CHCl3 before using as an anaesthetic is tested by

  • AgNO3 solution after boiling with KOH

  • Ammonical cuprous chloride

  • Fehling solution

  • AgNO3


346.

What is the correct order of acidity from weakest to strongest acid for these compounds :

  • I < IV < III < II

  • III < IV < III < II

  • IV < I < III < II

  • II < III < I < IV


347.

Lucas test is given by an alcohol within 5 minutes. 0.22 g of which liberates 56 mL of CH4 at STP on treating with CH3MgI. The structure of alcohol is

  • CH3 - CHOH - CH3

  • (CH3)2CH - CHOH - CH3

  • CH- CH2 - CHOH - CH3

  • (CH3)3C - CHOH - CH3


348.

The reaction in which phenol differs from alcohol is :

  • it undergoes esterification with carboxylic acid

  • it reacts with ammonia

  • it forms yellow crystals of iodoform

  • it liberates H2 with Na metal


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349.

The reaction involved in the oil of winter green test is :

Salicylic acid   product

The product is treated with Na2CO3 solution. The missing reagent in the above reaction is :

  • phenol

  • NaOH

  • ethanol

  • methanol


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350.

(CH3)3COCH3 and CH3OC2H5 are treated with hydroiodic acid. The fragments obtained after reactions are respectively

  • (CH3)3CI + CH3OH; CH3I + C2H5OH

  • (CH3)3CI + CH3OH; CH3OH + C2H5I

  • (CH3)3COH + CH3I; CH3OH + C2H5I

  • CH3I + (CH3)3COH; CH3I + C2H5OH


A.

(CH3)3CI + CH3OH; CH3I + C2H5OH

The fragments obtained after reaction of (CH3)3COCH3 and CH3OC2H5 with hydroiodic acid are (CH3)3CI + CH3OH; CH3I + C2H5OH. 

When mixed ethers are used, the formation of alkyl iodide depends on the nature of alkyl
groups. Methyl iodide is formed when one group is methyl and the other a primary or secondary alkyl group. This reaction follows SN2 mechanism and because of the steric effect of the larger group, I- attacks the smaller (Me) group.

CH3OC2H5 + HI  CH3I + C2H5OH

When the substrate is a methyl t-alkyl ether, the products are t-RI and MeOH. This reaction follows SN1 mechanism and formation of products is controlled by the stability of
carbocation. 

C(CH3)3OCH3 tert-Butyl methyl ether+ HI SN1373 K C(CH3)3Itert-Butyl iodide + CH3OH


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