The compound from which formic acid cannot be prepared is
methyl alcohol
carbon monoxide + NaOH
glycerol
methyl magnesium bromide
D.
methyl magnesium bromide
Formic acid (HCOOH) cannot be prepared from methyl magnesium bromide (CH,MgBr) while from all other reagents, it is obtained as
(a) CH3OH HCHO HCOOH
(b) CO + NaOH → HCOONa HCOOH + Na2SO4
(c) Glycerol + Oxalic acid HCOOH + glycerol
Following reaction
elimination reaction
free radical substitution
nucleophilic substitution
electrophilic substitution
Which alcohol of molecular formula C4H9OH cannot be obtained by the reduction of carbonyl compound ?
2-methyl propan-1-ol
2-methyl propan-2-ol
butanol
butan-2-ol
The correct order of boiling point for primary (1 °), secondary (2°) and tertiary (3°) alcohols is
1 ° >2° > 3°
3° >2° > 1
2° > 1 ° > 3°
2° >3° > 1
For the sequence of reactions
The compound A in the sequence is
2-butanone
acetaldehyde
acetone
propanal
The alcohol that produces turbidity immediately with ZnCl3/conc. HCl at room temperature
1-hydroxy butane
2-hydroxy butane
2-hydroxy-2-methyl propane
1-hydroxy-2-methyl propane