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ત્રિકોણમિતીય સમીકરણો અને ત્રિકોણના ગુણધર્મો

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ગણિત ધોરણ 11 સેમિસ્ટર 2

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ગણિત

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ત્રિકોણમિતીય સમીકરણો અને ત્રિકોણના ગુણધર્મો

નીચેનું સમીકરણ ઉકેલો :
$2 space cos space straight theta space plus space sec space straight theta space equals space 3$

નીચેનું સમીકરણ ઉકેલો :
$2 space cos space 2 straight theta space plus space square root of 2 space equals space 0$

નીચેનું સમીકરણ ઉકેલો :
$sin space 2 theta space plus space cos space theta space equals space 0$

therefore space 2 space sin space straight theta space cos space straight theta space plus space cos space straight theta space equals space 0 therefore space cos space straight theta space open parentheses 2 space sin space straight theta space plus space 1 close parentheses space equals space 0 therefore space cos space straight theta space equals space 0 space અથવ ા space sin space straight theta space equals space minus 1 half therefore straight theta space equals space open parentheses 2 straight k space plus space 1 close parentheses space straight pi over 2 space comma space straight k space element of space straight Z અથવ ા sin space straight theta space equals space minus 1 half space equals space sin space open parentheses negative straight pi over 6 close parentheses therefore space straight theta space equals space kπ space plus space open parentheses negative 1 close parentheses to the power of straight k space open parentheses negative straight pi over 6 close parentheses space comma space straight k space element of space straight Z therefore space straight theta space equals space kπ space minus space open parentheses negative 1 close parentheses to the power of straight k space straight pi over 6 space comma space straight k space element of space straight Z therefore space ઉક ે લગણ space colon space open curly brackets open parentheses bold 2 bold k bold space bold plus bold space bold 1 close parentheses bold space bold pi over bold 2 bold space left enclose bold space bold k bold space bold element of bold space bold Z end enclose close curly brackets bold space bold union bold space open curly brackets bold kπ bold space bold plus bold space open parentheses bold minus bold 1 close parentheses to the power of bold k bold space bold pi over bold 2 bold space left enclose bold space bold k bold space bold element of bold space bold Z end enclose close curly brackets

નીચેનું સમીકરણ ઉકેલો :
$4 space sin squared space straight theta space minus space 8 space cos space straight theta space plus space 1 space equals space 0$

નીચેનું સમીકરણ ઉકેલો :
$2 space cos squared space straight theta space plus space square root of 3 space cos space straight theta space equals space 0$

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