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વિકલન

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :

$fraction numerator 3 straight x space plus space 2 over denominator 2 straight x space plus space 3 end fraction space semicolon space x space equals space 1$ આગળ

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :

$cos space x space semicolon space x space equals space straight pi over 2$ આગળ

અહીં, f (x) = cos x

હવે, $straight x space equals space straight pi over 2$ આગળ f નો વિકલિત,

$straight f apostrophe space open parentheses straight pi over 2 close parentheses space equals space limit as straight h rightwards arrow 0 of space space fraction numerator straight f space open parentheses begin display style straight pi over 2 end style space plus space straight h close parentheses space minus space straight f space open parentheses begin display style straight pi over 2 end style close parentheses over denominator straight h end fraction space space space space space space space space space space space space space space space equals space limit as straight h rightwards arrow 0 of space space fraction numerator cos space open parentheses begin display style straight pi over 2 end style space plus space straight h close parentheses space minus space cos space begin display style straight pi over 2 end style over denominator straight h end fraction space space space space space space space space space space space space space space space equals space limit as straight h rightwards arrow 0 of space fraction numerator negative space sin space straight h space minus space 0 over denominator straight h end fraction space space space space space space space space space space space space space space equals space open parentheses negative 1 close parentheses space times space limit as straight h rightwards arrow 0 of space space fraction numerator sin space straight h over denominator straight h end fraction space space space space space space space space space space space space space equals space open parentheses negative 1 close parentheses space times space 1 space space space space space space space space space space space space space equals space bold minus bold 1$

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :
sin x ; x = 0 આગળ

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :
$1 over straight x space semicolon space x space equals space 1$ આગળ

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :

$3 straight x squared space minus space 2 straight x space plus space 1 space semicolon space straight x space equals space minus 1 space$ આગળ

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