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CBSE Gujarat Board Haryana Board

Previous Year Papers

Download the PDF Question Papers Free for off line practice and view the Solutions online.
Currently only available for
Class 10 Class 12

સમીકરણ

નીચેનું સમીકરણ ઉકેલો :
$bold 2 bold y bold space bold plus bold space bold 5 over bold 3 bold space bold equals bold space bold 26 over bold 3 bold space bold minus bold space bold y$

bold therefore bold space bold 3 bold y bold space bold equals bold space bold 26 over bold 3 bold minus bold 5 over bold 3 bold therefore bold space bold 3 bold y bold space bold equals bold space bold 21 over bold 3 bold therefore bold space bold 3 bold y bold space bold equals bold space bold 7 bold therefore bold space bold y bold space bold equals bold space bold 7 over bold 3 bold therefore bold space bold y bold space bold equals bold space bold 2 bold 1 over bold 3

નીચેનું સમીકરણ ઉકેલો :
$bold x over bold 2 bold space bold minus bold space bold 2 bold space bold equals bold space bold x over bold 3 bold space bold plus bold space bold 1$

નીચેનું સમીકરણ ઉકેલો :
$fraction numerator bold 2 bold x over denominator bold 3 end fraction bold space bold plus bold space bold 1 bold space bold equals bold space fraction numerator bold 7 bold x over denominator bold 15 end fraction bold space bold plus bold space bold 3$

નીચેનું સમીકરણ ઉકેલો :
3x + 8 = -5x + 4

નીચેનું સમીકરણ ઉકેલો :
$bold 5 bold x bold space bold plus bold space bold 7 over bold 2 bold space bold equals bold space fraction numerator bold 3 bold x over denominator bold 2 end fraction bold space bold minus bold space bold 14$

નીચેનું સમીકરણ ઉકેલો :
$bold x bold space bold equals bold space bold 4 over bold 5 bold space open parentheses bold x bold space bold plus bold space bold 10 close parentheses$

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