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 Multiple Choice QuestionsMultiple Choice Questions

1.

An astronaut is looking down on earth's surface from a space shuttle at an altitude of 400 km.
Assuming that the astronaut's pupil diameter is 5 mm and the wavelength of visible light is 500 nm, the astronaut will be able to resolve linear objects of the size about

  • 0.5 m

  • 5 m

  • 50 m

  • 500 m


C.

50 m

The resolving power of the eye is given by

         R = 1.22 λb × D

where λ is the wavelength of light

          b is the diameter of the lens 

          D is the distance from the lens at which light is focussed

d = 400 km = 400 × 103 m

d = 5 mm = 5 × 10-3 m

∴       R = 1.22 × 500 × 10-9 × 4 × 1055 × 10-3

          R = 48.8 

         R = 50 m


2.

A diver, at a depth of 12 metre from the surface of the water, sees the sky within a cone whose half vertex angle is : aμw=43

  • cos−143

  • sin−143

  • 90°

  • sin−134


D.

sin−134

Let diver is placed at S. He will see a cone of maximum radius r.

         

In this condition

          sin(ic) = 1aμw

      sin(ic)= 14/3

       sin(ic) = 34

            ic = sin134


3.

In an experiment to find the focal length of a concave mirror a graph is drawn between the magnitudes of u and v. The graph looks like 


C.

In case of concave mirror, when we move the object  from infinity to focus of the mirror ( i.e u decrease from  ∞ to f ), the image moves from focus to ∞ ( i.e v increase from f to  ∞). Therefore, the graph looks like the curve shown in fig (c).


4.

Assertion: Owls can move freely during night. 

Reason: They have large number of rods on their retina.

  • if both assertion and reason are true and the reason is the correct explanation of the assertion

  • if both assertion and reason are true and the reason is not the correct explanation of the assertion

  • if assertion is true but reason is false

  • if both assertion and reason are false statements


C.

if assertion is true but reason is false

There are two types of receptors in the eyes. One is called rods and other is cons. The rods are sensitive for dark light. As the owl has large number of cones in its retina and so the owl can move freely in the dark.


5.

 A light wave travels from glass to water. The refractive indices for glass and water are 32 and 43 respectively. The value of the critical angle will be :

  • sin-112

  • sin-198

  • sin-189

  • sin-157


C.

sin-189

From the relation,

     

        1sin C  = ωμg

or       1sinC = μgμω

where C = critical angle 

         μg = refractive index of glass = 3/2

         μω = refractive index of water= 4/3

                 sin C = μωμg

                     sin C = 4/33/2

                     sin C = 89

Hence,                C = sin-189


6.

The Cauchy's dispersion formula is

  • n = A + Bλ-2 + Cλ-4

  • n = A + Bλ-2 + Cλ4

  • n = A + Bλ2 + Cλ-4

  • n = A + Bλ2 + Cλ4


A.

n = A + Bλ-2 + Cλ-4

The Cauchy's dispersion formula represents the dispersion of most of the substances with considerable accuracy.

From Cauchy's dispersion formula if n is refractive index and A, B and C are constants for a given medium

The most general form of Cauchy's equation is

      n(λ) = A + Bλ2 + Cλ4 + ........

       n = A + Bλ-2 + Cλ-4 


7.

The magnification of an astronomical telescope is 10 and the focal length of eye-piece is 20 cm. The focal length of objective lens is

  • 1200 cm

  • 2 cm

  • 200 cm

  • 100 cm


C.

200 cm

Magnification of astronomical telescope 

             m = fofe

where, fo = focal length of objective lens 

           fe = focal length of eye piece

       10 = fo20

        fo = 10 × 20

        fo = 200 cm


8.

A convex lens of focal length 12 cm is made up of a glass of refractive index 32.When it is immersed in a liquid of refractive index 54, its focal length will be

  • 15 cm

  • 6 cm

  • 30 cm

  • 24 cm


C.

30 cm

Here: an32anw=54 , f1 = 12 cm

      wngnganwa = 3/25/4 = 65

              f2f1 = nga-1ngw-1

or         f212 = 3/2 -16/5-1

or           f2  =  1/21/5×12

Hence,    f2   = 30 cm


9.

Golden view of sea shell is due to

  • diffraction

  • polarisation

  • dispersion

  • reflection


B.

polarisation

When a ray of light falls on sea shell, then its small amount first gets refracted (slightly polarised) and then almost gets reflected back (fully polarised). That is why, view of sea shell is golden due to polarisation.


10.

Brilliance of diamond is due to

  • shape

  • reflection

  • cutting

  • total internal reflection


D.

total internal reflection

Total internal reflection can occur only when a ray is incident on the surface of a medium whose refractive index is smaller than that of the medium in which the ray is travelling. Since the refractive index of air is  1.00029  and that of a  diamond is 2.42, therefore brilliance of diamond is due to total internal reflection.