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The Solid State

Multiple Choice Questions

81.

The number of carbon atoms per unit cell of diamond unit cell is

82.

A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72 g cm³. The molar mass of the metal is (N_A vogadro's constant = 6.02x 10²³ mol^-1).

40 g mol^-1
30 g mol^-1
27g mol^-1
20 g mol^-1

83.

What is the co-ordination number of body centred cube ?

84.
A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :

C₃A₂

C₃A₄

C₄A₃

C₂A₃

C₃A₄

Anions(A) are in hcp, so number of anions (A) = 6

Cations(C) are in 75% O.V., so number of cations (C)

$= 6 \times \frac{3}{4} = \frac{18}{4} = \frac{9}{2}$

So formula of compound will be

$C_{\frac{9}{2}} A_{6} \Rightarrow C_{9} A_{12} C_{9} A_{12} \Rightarrow C_{3} A_{4}$

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Multiple Choice Questions

84. A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is : C3A2 C3A4 C4A3 C2A3

84.
A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :

C₃A₂

C₃A₄

C₄A₃

C₂A₃