The 14th term of an AP is twice its 8th term. If its 6th terms is -8, then find the sum of its first 20 terms.
Let a and d be the first term and the common difference of the AP, respectively.
∴ nth term of the AP, an = a + (n-1)d
So,
a14 = a+ (14-1)d = a + 13d
a8 = a + (8 - 1)d = a + 7d
a6 = a+ (6 - 1)d = a + 5d
According to the question,
a14 = 2a8
⇒ a + 13d = 2 (a + 7d)
⇒ a + d = 0 .... (i)
Also,
a6 = a + 5d = - 8 ... (ii)
solving (i) and (ii), we get
a = 2 and d = -2
∴ S20 = 20/2 [2 x 2 + (20 - 1)(-2)]
= - 340
Hence, the sum of the first 20 terms is -340.
If the coordinates of points A and B are (-2, -2) and (2, -4) respectively, find the coordinates of P such that AP = 3/7 AB, where P lies on the line segment AB.
Find the area of the minor segment of a circle of radius 14 cm, when its central angle is 60°. Also find the area of the corresponding major segment. [ use π = 22/7 ]
Due to sudden floods, some welfare associations jointly requested the government to get 100 tents fixed immediately and offered to contribute 50% of the cost. If the lower part of each tent is of the form of a cylinder of diameter 4.2 m and height 4 m with the conical upper part of same diameter but of height 2.8 m, and the canvas to be used costs Rs. 100 per sq. m, find the amount, the associations will have to pay. What values are shown by these associations? [ use π = 22/7]