The 14th term of an AP is twice its 8th term. If its 6th  terms is -8, then find the sum of its first 20 terms.
If the coordinates of points A and B are (-2, -2) and (2, -4) respectively, find the coordinates of P such that AP = 3/7 AB, where P lies on the line segment AB.
Find the area of the minor segment of a circle of radius 14 cm, when its central angle is 60°. Also find the area of the corresponding major segment.  [ use π = 22/7 ]
Due to sudden floods, some welfare associations jointly requested the government to get 100 tents fixed immediately and offered to contribute 50% of the cost. If the lower part of each tent is of the form of a cylinder of diameter 4.2 m and height 4 m with the conical upper part of same diameter but of height 2.8 m, and the canvas to be used costs Rs. 100 per sq. m, find the amount, the associations will have to pay. What values are shown by these associations? [ use π = 22/7]
Now,
Total surface area of the solid  = Total surface area of the cube + curved surface area of the hemisphere - Area of the base of the hemisphere
 = 6a2 + 2πr2 -πr2
= [ 6 x (10)2 + 2 x 3.14 x (5)2 - 3.14 x (5)2] cm2
 = (600 +157 -78.5 ) cm2
= 678.5 cm2
Cost of painting  = Rs 5 per 100 cm2
Therefore,Â
Cost of painting the solid = 678.5 x (5/100) = Rs. 33.90
Hence, the approximate cost of painting the solid so formed is Rs. 33.90