Subject

Mathematics

Class

CBSE Class 12

Pre Boards

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Sample Papers

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 Multiple Choice QuestionsShort Answer Type

21.

If straight x equals straight a space sint space and space straight y space equals space straight a open parentheses cost plus log space tan straight t over 2 close parentheses space find space fraction numerator straight d squared straight y over denominator dx squared end fraction

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22.

Evaluate: integral fraction numerator sin left parenthesis straight x minus straight a right parenthesis over denominator sin left parenthesis straight x plus straight a right parenthesis end fraction dx

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23.

Evaluate:
integral fraction numerator 5 straight x minus 2 over denominator left parenthesis 1 plus 2 straight x plus 3 straight x squared end fraction dx

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24.

Evaluate:
integral fraction numerator straight x squared over denominator left parenthesis straight x squared plus 4 right parenthesis left parenthesis straight x squared plus 9 right parenthesis end fraction dx


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25.

Evaluate: integral subscript 0 superscript 4 open parentheses open vertical bar straight x close vertical bar plus open vertical bar straight x minus 2 close vertical bar plus open vertical bar straight x minus 4 close vertical bar close parentheses dx

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26.

If straight a with rightwards arrow on top space and space straight b with rightwards arrow on top are two vectors such that open vertical bar straight a with rightwards arrow on top plus straight b with rightwards arrow on top close vertical bar equals open vertical bar straight a with rightwards arrow on top close vertical bar comma then prove that vector 2 straight a with rightwards arrow on top plus straight b with rightwards arrow on top is perpendicular to vector straight b with rightwards arrow on top.

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27.

Find the coordinates of the point, where the line fraction numerator straight x minus 2 over denominator 3 end fraction equals fraction numerator straight y plus 1 over denominator 4 end fraction equals fraction numerator straight z minus 2 over denominator 2 end fraction intersects the plane straight x minus straight y plus straight z minus 5 space equals space 0. Also find the angle between the line and the plane. 

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28.

Find the vector equation of the plane which contains the line of intersection of the planes. straight r with rightwards arrow on top. open parentheses straight i with hat on top plus 2 straight j with hat on top plus 3 straight k with hat on top close parentheses minus 4 space equals 0 and straight r with rightwards arrow on top. open parentheses 2 straight i with hat on top plus straight j with hat on top minus straight k with hat on top close parentheses plus 5 space equals 0 and which is perpendicular to the plane straight r with rightwards arrow on top. space open parentheses 5 straight i with hat on top plus 3 straight j with hat on top minus 6 straight k with hat on top close parentheses plus 8 space equals space 0


The equation of the given planes are
straight r with rightwards arrow on top. open parentheses straight i with hat on top plus 2 straight j plus 3 straight k with hat on top close parentheses minus 4 space equals space 0 space space... left parenthesis 1 right parenthesis
straight r with rightwards arrow on top. left parenthesis 2 straight i with hat on top plus straight j with hat on top minus straight k with hat on top right parenthesis plus 5 space equals space 0 space space space... left parenthesis 2 right parenthesis
The equation of the plane passing through the intersection of the planes (1) and (2) is
open square brackets straight r with rightwards arrow on top. open parentheses straight i with hat on top plus 2 straight j with hat on top plus 3 straight k with hat on top close parentheses minus 4 close square brackets plus straight lambda open square brackets straight r with rightwards arrow on top. open parentheses 2 straight i with hat on top plus straight j with hat on top minus straight k with hat on top close parentheses plus 5 close square brackets equals 0
space space rightwards double arrow space space straight r with rightwards arrow on top open square brackets open parentheses 1 plus 2 straight lambda close parentheses straight i with hat on top plus left parenthesis 2 plus straight lambda right parenthesis straight j with hat on top plus left parenthesis 3 minus straight lambda right parenthesis straight k with hat on top close square brackets space equals space 4 minus 5 straight lambda space space space... left parenthesis 3 right parenthesis
Given that plane (3) is perpendicular to the plane straight r with rightwards arrow on top. open parentheses 5 straight i with hat on top plus 3 straight j with hat on top minus 6 straight k with hat on top close parentheses plus 8 space equals space 0
open parentheses 1 plus 2 straight lambda close parentheses cross times 5 plus left parenthesis 2 plus straight lambda right parenthesis cross times 3 plus left parenthesis 3 minus straight lambda right parenthesis cross times left parenthesis negative 6 right parenthesis space equals space 0
rightwards double arrow space space 19 straight lambda minus 7 space equals space 0
rightwards double arrow space space space straight lambda space equals space 7 over 19
Putting space straight lambda space equals space 7 over 19 space in space left parenthesis 3 right parenthesis comma space we space get

straight r with rightwards arrow on top open square brackets open parentheses 1 plus 14 over 19 close parentheses straight i with hat on top plus open parentheses 2 plus 7 over 19 close parentheses straight j with hat on top plus open parentheses 3 minus 7 over 19 close parentheses straight k with hat on top close square brackets space equals space 4 minus 35 over 19
rightwards double arrow space space straight r with rightwards arrow on top. open parentheses 33 over 19 straight i with hat on top plus 45 over 19 straight j with hat on top plus 50 over 19 straight k with hat on top close parentheses space equals space 41 over 19
rightwards double arrow space space straight r with rightwards arrow on top. open parentheses 33 straight i with hat on top plus 45 straight j with hat on top plus 50 straight k with hat on top close parentheses space equals space 41
This is the equation of the required line. 

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29.

A speaks truth in 60% of the cases, while B in 90% of the cases. In what percent of cases are they likely to contradict each other in stating the same fact? In the cases of contradiction do you think, the statement of B will carry more weight as he speaks truth in more number of cases than A?

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 Multiple Choice QuestionsLong Answer Type

30.

Using integration, find the area bounded by the curve x2 = 4y and the line x = 4y – 2.

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