Subject

Mathematics

Class

CBSE Class 12

Pre Boards

Practice to excel and get familiar with the paper pattern and the type of questions. Check you answers with answer keys provided.

Sample Papers

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 Multiple Choice QuestionsShort Answer Type

21.

The random variable X can take only the values 0, 1, 2, 3. Given that P(X =0) = P(X = 1) = p and P(X = 2) = P(X = 3) such that Σpixi2 = 2Σpixi, find the value of p.

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22.

Often it is taken that a truthful person commands, more respect in the society. A man is known to speak the truth 4 out of 5 times. He throws a die and reports that it is a six.
Find the probability that it is actually a six.
Do you also agree that the value of truthfulness leads to more respect in the society?

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23.

Solve the following L.P.P. graphically :
Minimise Z = 5x + 10y
Subject to x + 2y ≤ 120
Constraints x + y ≥ 60
x – 2y ≥ 0
and x, y ≥ 0

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 Multiple Choice QuestionsLong Answer Type

24.

Use product open square brackets table row 1 cell negative 1 end cell 2 row 0 2 cell negative 3 end cell row 3 cell negative 2 end cell 4 end table close square brackets space space open square brackets table row cell negative 2 end cell 0 1 row 9 2 cell negative 3 end cell row 6 1 cell negative 2 end cell end table close square bracketsto solve the system of equations x + 3z = 9,
–x + 2y – 2z = 4, 2x – 3y + 4z = –3

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25.

Discuss the commutativity and associativity of binary operation '*' defined on A = Q − {1} by the rule a * b = a − b + ab for all, a, b ∊ A. Also find the identity element of * in A and hence find the invertible elements of A. 

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26.

Consider f : R+ → [−5, ∞), given by f(x) = 9x2 + 6x − 5. Show that f is invertible with f−1(y)open parentheses fraction numerator square root of straight y plus 6 end root minus 1 over denominator 3 end fraction close parentheses.

Hence Find
(i) f−1(10)
(ii) y if f−1(y)=43,

where R+ is the set of all non-negative real numbers.

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27.

If the sum of lengths of the hypotenuse and a side of a right angled triangle is given, show that the area of the triangle is maximum, when the angle between them is π/3.

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28.

Solve the differential equation straight x dy over dx space plus straight y space equals space straight x space cos space straight x space plus space sin space straight x comma space given space that space straight y space equals space 1 space when space straight x space equals space straight x over 2

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29.

Prove that x2 – y2 = c(x2 + y2)2 is the general solution of the differential equation (x3 – 3xy2)dx = (y3 – 3x2y) dy, where C is a parameter.

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30.

If straight a with rightwards arrow on top comma straight b with rightwards arrow on top comma space and space straight c with rightwards arrow on top are mutually perpendicular vectors of equal magnitudes, show that the vector stack straight a space with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top is equally straight a with rightwards arrow on top comma straight b with rightwards arrow on top comma space and space straight c with rightwards arrow on top inclined to Also, find the angle which stack straight a space with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top with straight a with rightwards arrow on top comma space straight b with rightwards arrow on top space or space straight c with rightwards arrow on top.


Since straight a with rightwards arrow on top space comma straight b with rightwards arrow on top space and space straight c with rightwards arrow on top are mutually perpendicular vectors, we have
stack straight a. with rightwards arrow on top straight b with rightwards arrow on top space equals stack straight b. with rightwards arrow on top straight c with rightwards arrow on top space equals space stack straight c. with rightwards arrow on top straight a with rightwards arrow on top space equals space 0
It is given that

vertical line straight a with rightwards arrow on top vertical line space equals vertical line straight b with rightwards arrow on top vertical line space equals vertical line straight c with rightwards arrow on top vertical line
Let space vector space straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top space be space inclined space to space straight a with rightwards arrow on top comma space straight b with rightwards arrow on top space and space straight c with rightwards arrow on top space at space angles space straight theta subscript 1 comma straight theta subscript 2 space and space straight theta subscript 3 space
respectively.
Then comma
cos space straight theta subscript 1 space equals space fraction numerator open parentheses straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top close parentheses. straight a with rightwards arrow on top over denominator vertical line straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top vertical line vertical line straight a with rightwards arrow on top vertical line end fraction space equals space fraction numerator straight a with rightwards arrow on top. straight a with rightwards arrow on top space plus straight b with rightwards arrow on top. straight c with rightwards arrow on top space plus straight c with rightwards arrow on top. straight a with rightwards arrow on top over denominator vertical line straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top vertical line vertical line straight a with rightwards arrow on top vertical line end fraction
space equals space fraction numerator vertical line straight a with rightwards arrow on top vertical line squared over denominator vertical line straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top vertical line vertical line straight a with rightwards arrow on top vertical line end fraction space left square bracket straight b with rightwards arrow on top. straight a with rightwards arrow on top space equals space straight c with rightwards arrow on top. straight a with rightwards arrow on top space equals space 0 right square bracket
equals fraction numerator vertical line straight a with rightwards arrow on top vertical line over denominator vertical line straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top vertical line end fraction
cos space straight theta subscript 2 space equals space fraction numerator open parentheses straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top close parentheses. straight b with rightwards arrow on top over denominator vertical line straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top vertical line vertical line straight b with rightwards arrow on top vertical line end fraction space equals space fraction numerator straight a with rightwards arrow on top. straight b with rightwards arrow on top space plus straight b with rightwards arrow on top. straight b with rightwards arrow on top space plus straight c with rightwards arrow on top. straight b with rightwards arrow on top over denominator vertical line straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top vertical line vertical line straight b with rightwards arrow on top vertical line end fraction
fraction numerator vertical line straight b with rightwards arrow on top vertical line squared over denominator vertical line straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top vertical line vertical line straight b with rightwards arrow on top vertical line end fraction space left square bracket straight a with rightwards arrow on top. straight b with rightwards arrow on top space equals space straight c with rightwards arrow on top. straight b with rightwards arrow on top space equals space 0 right square bracket
equals fraction numerator vertical line straight b with rightwards arrow on top vertical line over denominator vertical line straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top vertical line end fraction
cos space straight theta subscript 3 space equals space fraction numerator open parentheses straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top close parentheses. straight c with rightwards arrow on top over denominator vertical line straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top vertical line vertical line straight c with rightwards arrow on top vertical line end fraction space equals space fraction numerator straight a with rightwards arrow on top. straight c with rightwards arrow on top space plus straight b with rightwards arrow on top. straight c with rightwards arrow on top space plus straight c with rightwards arrow on top. straight c with rightwards arrow on top over denominator vertical line straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top vertical line vertical line straight c with rightwards arrow on top vertical line end fraction
fraction numerator vertical line straight c with rightwards arrow on top vertical line squared over denominator vertical line straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top vertical line vertical line straight c with rightwards arrow on top vertical line end fraction space left square bracket straight a with rightwards arrow on top. straight c with rightwards arrow on top space equals space straight b with rightwards arrow on top. straight c with rightwards arrow on top space equals space 0 right square bracket
equals fraction numerator vertical line straight c with rightwards arrow on top vertical line over denominator vertical line straight a with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top vertical line end fraction
Now comma space as space vertical line straight a with rightwards arrow on top vertical line space equals vertical line straight b with rightwards arrow on top vertical line space equals space vertical line straight c with rightwards arrow on top vertical line space comma cos space straight theta subscript 1 space equals space cosθ subscript 2 space equals space cos space straight theta subscript 3
therefore space straight theta subscript 1 space equals straight theta subscript 2 space equals straight theta subscript 3

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