Subject

Physics

Class

ICSE Class 10

Pre Boards

Practice to excel and get familiar with the paper pattern and the type of questions. Check you answers with answer keys provided.

Sample Papers

Download the PDF Sample Papers Free for off line practice and view the Solutions online.
Advertisement

 Multiple Choice QuestionsShort Answer Type

21.

State two advantages of an electromagnet over a permanent magnet. 

851 Views

22.

i) What will happen to a compass needle when the compass is placed below a wire and a current is made to flow through the wire? Give a reason to justify your answer.

ii) What energy conversion takes place during the working of a d.c. motor? 
643 Views

23.

A certain radioactive nucleus emits a particle that leaves its mass unchanged, but increases its atomic number by one. Identify the particle and write its symbol. 

335 Views

24.

i) Define the thermionic emission.

ii) Mention one use of thermionic emission.

iii) Name a substance, which is a good thermionic emitter. 
354 Views

Advertisement
25.

State the properties that are common to and shown by both beta rays and cathode rays. 

360 Views

 Multiple Choice QuestionsLong Answer Type

26.

PQ and PR are two light rays emerging from the object P as shown in the figure below:

i) What is the special name given to the angle of incidence (< PQN) of ray PQ?

ii) Copy the ray diagram and complete it to show the position of the image of the object P when seen obliquely from above.

iii) Name the phenomenon that occurs if the angle of incidence

443 Views

Advertisement

27.

A piece of iron of mass 2.0 kg has a thermal capacity of 966 J/o C.

i) How much heat is needed to warm it by 15 degree C?

ii) What is it’s specific heat capacity in S.I. Units?


Given: m = 2.0 kg, Thermal capacity = 966 J/oC

i) Rise in temperature = 15 oC

Thermal capacity (C) equals space fraction numerator Heat straight space required over denominator Rise straight space in straight space temperature end fraction 

Therefore, heat needed = 966 x 15 = 14490 J

ii) Specific heat capacity (c),

 equals fraction numerator Amount straight space of straight space heat over denominator Mass straight space cross times straight space rise straight space in straight space temperature end fraction straight space
equals straight space fraction numerator 14490 over denominator 2.0 straight space cross times straight space 15 end fraction straight space
equals straight space 14490 over 30 straight space
equals straight space 483 straight space straight J divided by kg divided by to the power of straight o straight C

698 Views

Advertisement
28.

In the figure below, the ammeter A reads 0.3 A. Calculate: 



i) the total resistance of the circuit.

ii) the value of R.

iii) the current flowing through r.

442 Views

Advertisement
Advertisement