Subject

Physics

Class

ICSE Class 10

Pre Boards

Practice to excel and get familiar with the paper pattern and the type of questions. Check you answers with answer keys provided.

Sample Papers

Download the PDF Sample Papers Free for off line practice and view the Solutions online.
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 Multiple Choice QuestionsShort Answer Type

21.

State two advantages of an electromagnet over a permanent magnet. 

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22.

i) What will happen to a compass needle when the compass is placed below a wire and a current is made to flow through the wire? Give a reason to justify your answer.

ii) What energy conversion takes place during the working of a d.c. motor? 
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23.

A certain radioactive nucleus emits a particle that leaves its mass unchanged, but increases its atomic number by one. Identify the particle and write its symbol. 

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24.

i) Define the thermionic emission.

ii) Mention one use of thermionic emission.

iii) Name a substance, which is a good thermionic emitter. 
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25.

State the properties that are common to and shown by both beta rays and cathode rays. 

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 Multiple Choice QuestionsLong Answer Type

26.

PQ and PR are two light rays emerging from the object P as shown in the figure below:

i) What is the special name given to the angle of incidence (< PQN) of ray PQ?

ii) Copy the ray diagram and complete it to show the position of the image of the object P when seen obliquely from above.

iii) Name the phenomenon that occurs if the angle of incidence

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27.

A piece of iron of mass 2.0 kg has a thermal capacity of 966 J/o C.

i) How much heat is needed to warm it by 15 degree C?

ii) What is it’s specific heat capacity in S.I. Units?

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28.

In the figure below, the ammeter A reads 0.3 A. Calculate: 



i) the total resistance of the circuit.

ii) the value of R.

iii) the current flowing through r.


i) We know, V = IR

Error converting from MathML to accessible text. 

ii) Total resistance, R = 20 ohm

Therefore,

Resistors are in parallel. 

1 over 20 equals 1 over straight R plus 1 over 60

rightwards double arrow 1 over straight R equals 1 over 20 minus 1 over 60

rightwards double arrow 1 over straight R equals fraction numerator 3 minus 1 over denominator 60 end fraction equals 2 over 60 equals 1 over 30

rightwards double arrow straight R equals 30 straight capital omega
 

iii) We know that,

V = IR

Potential (V) is equal at the two ends.

Let, I1 be the current flowing through R and I2 be through 60 ohm.

I1 + I2 = 0.3

I2=(0.3-I1)

Now, we have V=V

That is,

I1R1 = I2R2

Ix 30= (0.3-I1) x 60

    I1  = 0.6 – 2I1

    3I1=0.6

straight I subscript 1 space end subscript equals fraction numerator 0.6 over denominator 3 end fraction equals 0.2 space
Therefore,

Current flowing through R = 0.2 A

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