Ratio of loss in solvent to gain in CaCl2 tube is from Chemistry

Subject

Chemistry

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

21.

The IUPAC name of the following compound is

  • 3-ethyl-2-methylbutanal

  • 2, 3-dimethylpentanal

  • 2-ethyl-3-methylbutanal

  • 2-ethyl-3-methylbutan-3-al


22.

Oxidation potential of unimoles of calomel is

  • + 0.25 V

  • 0.00 V

  • + 0.287 V

  • -0.28 V


23.

1 C electricity deposits

  • 10.8 g of Ag

  • 96500 g of Ag

  • electrochemical equivalent of Ag

  • half of electrochemical equivalent of Ag


24.

Given, for Sn4+/ Sn2+, standard reductiona potential is 0.15 V and for Au3+/ Au, standard reduction potential is 1.5 V.

For the reaction,

3Sn2+ + 2Au3+ → 3Sn4+ + 2Au

the value of Ecell° is

  • +1.35

  • +2.55

  • -1.35

  • -2.55


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25.

The isotope tha causes skin disease is

  • I131

  • S35

  • P31

  • None of these


26.

The first order integrated rate equation is

  • k = xt

  • k = 2.303t logaa - x

  • k = 1t  ln aa - x

  • k = 1txa(a - x)


27.

For nuclear fusion reactions, the fusion temperature is of the order of

  • 105 K

  • 103 K

  • 107 K

  • 100 K


28.

The units of rate constant for first order reaction are

  • mol L-1s-1

  • s-1

  • Lmol-1s-1

  • L2mol-2s-1


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29.

German silver does not contain

  • Sn

  • Cu

  • Zn

  • Ni


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30.

Ratio of loss in solvent to gain in CaCl2 tube is

  • p°p

  • pp°

  • p° - pp°

  • p - p°p


C.

p° - pp°

 Loss in the weight of solvent = p° - p

    Gain in the weight of CaCl2 tube = p°

 Loss in the weight of solventGain in the weight of CaCl2 tube = p° - pp°


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