Consider the following sets of quantum numbers. Which of the following setting is not permissible arrangement of electrons in an atom?
n = 4; l = 0; m = 0; s =
n = 5; l = 3; m = 0; s =
n = 3; l = 2; m = -2; s =
n = 3; l = 2; m = -3; s =
HCl gas is covalent and NaCl is an ionic compound. This is because
sodium is highly electropositrve
hydrogen is a non-metal
HCl is a gas
electronegativity difference between H and Cl is less than 2.1
Main axis of diatomic molecule is z. The orbitals px and py overlap to form
-molecular orbital
σ-molecular orbital
δ-molecular orbital
No bond is formed
An organic compound contains C = 40%, H = 13.33% and N = 46.67%. Its empirical formula is
C2H2N
C3H7N
CH4N
CHN
Benzene carbaldehyde is reacted with conc. NaOH solution to give the products A and B. The product A can be used as a food preservative and the product B is an aromatic hydroxy compound, where -OH group is linked to sp3-hybridised C-atom next to benzene ring. The products A and B respectively are
sodium benzoate and phenol
sodium benzoate and phenyl methanol
sodium benzoate and cresol
sodium benzoate and picric acid
B.
sodium benzoate and phenyl methanol
When benzene carbaldehyde reacts with NaOH, it proceeds via Cannizzaro reaction. It is a disproportionation reaction in which half of the molecules of aldehyde are oxidised and other half are reduced.
An organic compound A on reduction gives compound B, which on reaction with trichloromethane and caustic potash forms C. The compound C on catalytic reduction gives N-methyl benzenamine, the compound A is,
nitrobenzene
nitromethane
methanamine
benzenamine
The hybridisation of C in diamond, graphite and ethyne is in the order.
sp3, sp, sp2
sp3, sp2, sp
sp, sp2, sp3
sp2, sp3, sp