Consider the following sets of quantum numbers. Which of the following setting is not permissible arrangement of electrons in an atom?
n = 4; l = 0; m = 0; s =
n = 5; l = 3; m = 0; s =
n = 3; l = 2; m = -2; s =
n = 3; l = 2; m = -3; s =
HCl gas is covalent and NaCl is an ionic compound. This is because
sodium is highly electropositrve
hydrogen is a non-metal
HCl is a gas
electronegativity difference between H and Cl is less than 2.1
Main axis of diatomic molecule is z. The orbitals px and py overlap to form
-molecular orbital
σ-molecular orbital
δ-molecular orbital
No bond is formed
An organic compound contains C = 40%, H = 13.33% and N = 46.67%. Its empirical formula is
C2H2N
C3H7N
CH4N
CHN
Benzene carbaldehyde is reacted with conc. NaOH solution to give the products A and B. The product A can be used as a food preservative and the product B is an aromatic hydroxy compound, where -OH group is linked to sp3-hybridised C-atom next to benzene ring. The products A and B respectively are
sodium benzoate and phenol
sodium benzoate and phenyl methanol
sodium benzoate and cresol
sodium benzoate and picric acid
An organic compound A on reduction gives compound B, which on reaction with trichloromethane and caustic potash forms C. The compound C on catalytic reduction gives N-methyl benzenamine, the compound A is,
nitrobenzene
nitromethane
methanamine
benzenamine
The hybridisation of C in diamond, graphite and ethyne is in the order.
sp3, sp, sp2
sp3, sp2, sp
sp, sp2, sp3
sp2, sp3, sp
B.
sp3, sp2, sp
(i) As diamond has tetrahedral structure in which all the C-atoms are bonded by4 σ-bonds with 4 neighbouring C-atoms. Thus, it has sp3 hybridisation.
(ii) Graphite forms an hexagonal sheet like structure in which each C-atom is bonded by 3 σ-bonds with 3-C atoms in the same plane, 4th electron of C-atom is free to move thus, show sp2 hybridisation.
(iii) Ethyne has CH≡CH structure, in which one C-atom is bonded with other C-atom through only one σ-bond (as -bonds do not take part in hybridisation). Thus, it shows sp-hybridisation.
Hence, correct order is : sp3, sp2, sp.