Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

11.

Wat is compiler?

  • Applcaton software

  • System software

  • Utility software

  • All of these


12.

The coefficient of x4 in (1 + x + x3 + x4)10 is

  • 210

  • 100

  • 310

  • 110


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13.

The locus of centre of circles which cuts orthogonally the circle x2 + y2 - 4x + 8 = 0 and touches x + 1 = 0, is

  • y2 + 6x + 7 = 0

  • x2 + y2 + 2x + 3 = 0

  • x2 + 3y + 4 = 0

  • None of the above


A.

y2 + 6x + 7 = 0

x2 + y2 + 2gx + 2fy + c = 0

Given equation of circle is

x2 + y2 - 4x + 8 = 0

The centres of above circles are (- g, - f) and (2, 0)

Condition of orthogonality is

2(g1g2 + f1f2) = c1 + c2

 2g × - 2 + f × 0 = c+ 8                             - 4g = c + 8       ...i

Also, the assume circle touch the lme x + 1 = 0.

The perpendicular drawn from centre to the line is equal to radius

   - g + 112 = g2 + f2 - c -   g + 1 = g2 + f2 - c

On squaring both sides, we get

g2 + 1 - 2 = g2 + f2 - c            c = f2 + 2g - 1

Putting the value of c in Eq (i), we get

4g = f2 + 2 - 1 + 8

 f2 + 2g + 4g + 7 = 0          f2 + 6g + 7 = 0

Thus, locus of circle is y2 + 6x + 7 = 0.


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14.

The condition for the line lx + my + n = 0 to be a normal to x225 + y29 = 1 is

  • l29 + m2l25 = n2256

  • 9m2 + 25l2 = 256n2

  • l29 - m2l25 = n2256

  • None of these


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15.

The least value of a, for which the function a 4sinx + 11 - sinx has at east one solution in the interval 0, π2, is

  • 9

  • 4

  • 5

  • 1


16.

If one line ofregression coefficient is less than unity, then the other will be

  • less than unity

  • equal to unity

  • greater than unity

  • All of these


17.

Roots of equation x3 - 6x + 1 = 0 lie in the interval

  • (2, 3)

  • (3, 4)

  • (3, 5)

  • (4, 6)


18.

RAM is a

  • volatile memory

  • non-volatile memory

  • cash memory

  • dynamic memory


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19.

If limnlogn + r - lognn = 2log2 - 12, then limn1nλn + 1λn + 2λ ... n + nλ1n is equal to

  • 4λe

  • 4eλ

  • 4e1λ

  • e4λ


20.

limx0sinsinx - sinxax3 + bx5 + c = - 112, then

  • a = 2, b  R, c = 0

  • a = - 2, b  R, c = 0

  • a = 1, b  R, c = 0

  • a = - 1, b  R, c = 0


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