The locus of centre of circles which cuts orthogonally the circle x2 + y2 - 4x + 8 = 0 and touches x + 1 = 0, is
y2 + 6x + 7 = 0
x2 + y2 + 2x + 3 = 0
x2 + 3y + 4 = 0
None of the above
The least value of a, for which the function a has at east one solution in the interval , is
9
4
5
1
If one line ofregression coefficient is less than unity, then the other will be
less than unity
equal to unity
greater than unity
All of these
Roots of equation x3 - 6x + 1 = 0 lie in the interval
(2, 3)
(3, 4)
(3, 5)
(4, 6)
A.
(2, 3)
Here, we see that f(2) and f(3) have opposite signs, so one of the roots lies in (2, 3).